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nordsb [41]
3 years ago
10

Identify the statement(s) that are both biconditional and false. Three points are not in the same plane if and only if exactly o

ne line passes through them. Exactly one line passes through three points if the points are in an infinite number of planes. an infinite number of planes pass through the same three points if and only if the points are not on the same line. three points on the same line if and only if exactly one plane passes through them. ​
Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0

Answer:

Step-by-step explanation:

1) Three points are not in the same plane if and only if exactly one line passes through them.

It is biconditional and false because more than one plane can pass through three points

2)Exactly one line passes through three points if the points are in an infinite number of planes.

It is biconditional and true because three points on same line will be in more than one plane and if they are not in the same plane then connect them and it will form a triangle which is in only one plane

3). an infinite number of planes pass through the same three points if and only if the points are not on the same line.

It is biconditional and false because more than one plane passes through them So, infinite no. of planes passes through them

4). three points on the same line if and only if exactly one plane passes through them. ​

It is biconditional and false because more than one plane passes through them So, infinite no. of planes passes through them

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45) The function corresponds to graph A

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Step-by-step explanation:

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The function g(x) is given by:

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Let's use the same method here.

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Let's use the same method here.

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g(x)=(x-2)^{2}+1+2

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Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

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Evaluatinf g(x) at this value of x we have:

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<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

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