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erica [24]
3 years ago
5

A rectangular lot whose perimeter is 340ft is fenced along three sides. An expensive fencing along the lot's length cost $42 per

foot. An inexpensive fencing along the two sides widths cost only $6 per foot. An inexpensive fencing along the two sides width cost only $6 per foot. The total cost of the fencing along the three sides comes to $5340. What are the lot's dimensions?
Mathematics
2 answers:
mezya [45]3 years ago
7 0

Answer:

95x521 ft

Step-by-step explanation:


Anon25 [30]3 years ago
5 0
220 ft in cheap fence
and 95.71 in expensive <span />
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Answer:

\tan \left(\frac{\sin \left(x\right)-\cos \left(x\right)}{\cos \left(x\right)+\sin \left(x\right)}\right)

Step-by-step explanation:

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What is 9 to the power of 6 divided by negative 2 to the power of 3?
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  A.  (1 2/3, 4 2/3)

Step-by-step explanation:

If you graph the equations, you see the lines intersect at the solution point:

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Expand and Simplify <br> 4( b+3) + 2 (b + 5)
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Each contestant in the Hunger Games must be trained to compete. Suppose that the time it takes to train a contestant has mean 5
LiRa [457]

Answer:

11.51% probability that it will take less than 450 days to train all the contestants.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sum of n variables, the mean is \mu*n and the standard deviation is s = \sigma\sqrt{n}

In this question:

n = 100, \mu = 100*5 = 500, s = 4\sqrt{100} = 40

Approximate the probability that it will take less than 450 days to train all the contestants.

This is the pvalue of Z when X = 450.

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{450 - 500}{40}

Z = -1.2

Z = -1.2 has a pvalue of 0.1151

11.51% probability that it will take less than 450 days to train all the contestants.

8 0
3 years ago
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