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dedylja [7]
2 years ago
7

Consider a large number of hydrogen atoms with electrons randomly distributed in the n = 1, 2, 3, and 4 orbits. How many differe

nt wavelengths of light are emitted by these atoms as the electrons fall into lower-energy orbitals? Calculate the lowest and highest energies of light produced by the transitions described in part (a). Calculate the frequencies and wavelengths of the light produced by the transitions described in part (b).
Chemistry
1 answer:
baherus [9]2 years ago
6 0
It would be 5 you know this
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Sodium chloride procedure​
MAVERICK [17]

Answer: Dissolve approximately 3 mg of Sodium Chloride in 2 mL of water.

Add 0.4 mL of silver nitrate TS and acidify with diluted nitric acid.

8 0
2 years ago
Fill in the coefficients that was will balance the following reaction SnSO4 + KBr SnBr2 K2SO4
Juliette [100K]

The coefficients are 1 : 2 : 1 : 1

<u>Explanation:</u>

To be a balanced equation, the chemical equation should have has equal number of atoms on both reactant and product side.

Given chemical equation:

        a_{0} {SnSO}_{4}+a_{1} K B r \rightarrow a_{2} {SnBr}_{2}+a_{3} K_{2} S O_{4}

Now, calculate the number of atoms present in reactant side:

Sn - 1

S O_{4} - 1

K - 1

Br - 1

Then, calculate the number of atoms present in product side:

Sn - 1

S O_{4} - 1

K - 2

Br - 2

Therefore, in order to balance this given chemical equation multiply KBr by 2 on reactant side. So, the balanced chemical equation is as follows.

       \Sn S O_{4}+2 K B r \rightarrow S n B r_{2}+K_{2} S O_{4}

Hence,

a_{0} - 1\\a_{1} - 2\\a_{2} - 1\\a_{3} - 1

8 0
3 years ago
Germanium has a face-centered cubic unit cell. The density of germanium is 5.32 g/cm3. Calculate a value for the atomic radius o
Cloud [144]

Answer:

1.59x10⁻¹⁰m

Explanation:

To solve this question we must know that the length of the cubic cell, X, is equal to:

X = √8 * R

<em>Where R is the atomic radius of germanium</em>

And that in 1 unit cell there are 4 atoms of germanium.

To solve this question we must find the mass in 1 unit cell, with this mass we can find the volume of the cube and the length. With the length we can know the atomic radius:

<em>Mass in 1 unit cell -Molar mass Ge = 72.64g/mol:</em>

4 atoms Ge * (1mol / 6.022x10²³ atoms) = 6.64x10⁻²⁴ moles Ge

6.64x10⁻²⁴ moles Ge * (72.64g / mol) = 4.825x10⁻²²g Ge

<em>Volume unit cell:</em>

4.825x10⁻²²g Ge * (1cm³ / 5.32g) = 9.07x10⁻²³cm³

<em>Length unit cell:</em>

∛9.07x10⁻²³cm³ = 4.49x10⁻⁸cm * (1m / 100cm) = 4.49x10⁻¹⁰m

<em>Atomic radius Ge:</em>

4.49x10⁻¹⁰m / √8 =

<h3>1.59x10⁻¹⁰m</h3>
7 0
3 years ago
Which of the following is an advantage angiosperms and gymnosperms have over mosses?
Valentin [98]

Answer:

they are seed producing so can populate more areas

8 0
3 years ago
Which of these elements is a noble gas? A. hydrogen (H) B. barium (Ba) C. nitrogen (N) D. krypton (Kr) E. bromine (Br)
Novosadov [1.4K]

Krypton is a noble gas! Hope this helps!

5 0
2 years ago
Read 2 more answers
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