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allsm [11]
3 years ago
12

How many moles of disulfur decafluoride are present in 3.99 x 104 molecules of this compound? moles

Chemistry
1 answer:
arsen [322]3 years ago
6 0

<u>Answer:</u> The number of moles of disulfur decafluoride is 6.62\times 10^{-20}

<u>Explanation:</u>

We are given:

Number of disulfur decafluoride molecules = 3.99\times 10^4

According to mole concept:

6.022\times 10^{23} number of molecules are contained in 1 mole of a compound.

So, 3.99\times 10^4 number of molecules will be contained in = \frac{1mol}{6.022\times 10^{23}}\times 3.99\times 10^{4}=6.62\times 10^{-20}mol of disulfur decafluoride.

Hence, the number of moles of disulfur decafluoride is 6.62\times 10^{-20}

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How many moles are represented by 118g of cobalt? Cobalt had an atomic mass of 58.93amu
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How do substances and mixtures diifer
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3 years ago
Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm
8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

\frac{dV}{dt}=10\frac{cm^3}{s}

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

\frac{dh}{dt} = ?*\frac{dV}{dt}

Of course, ?=\frac{dh}{dV}.

Now, since the volume of a cone is V=\pi r^2h/3 and the ratio r/h=15/20=3/4 or r=3/4h, the volume becomes:

V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3

We proceed to its differentiation:

\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}

Then, we compute \frac{dh}{dt}

\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}

Finally, at h=2:

\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}

Best regards.

4 0
3 years ago
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