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allsm [11]
3 years ago
12

How many moles of disulfur decafluoride are present in 3.99 x 104 molecules of this compound? moles

Chemistry
1 answer:
arsen [322]3 years ago
6 0

<u>Answer:</u> The number of moles of disulfur decafluoride is 6.62\times 10^{-20}

<u>Explanation:</u>

We are given:

Number of disulfur decafluoride molecules = 3.99\times 10^4

According to mole concept:

6.022\times 10^{23} number of molecules are contained in 1 mole of a compound.

So, 3.99\times 10^4 number of molecules will be contained in = \frac{1mol}{6.022\times 10^{23}}\times 3.99\times 10^{4}=6.62\times 10^{-20}mol of disulfur decafluoride.

Hence, the number of moles of disulfur decafluoride is 6.62\times 10^{-20}

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According to each substances heat of fusion, which of the items below requires more heat to be added per gram of substance to go
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<u>Answer: </u>The correct answer is Silver.

<u>Explanation:</u>

Specific heat of fusion is defined as the amount of heat which is required to raise the temperature of 1 gram of a substance to 1°C. It is generally expressed in kJ/mol

We are required to find the substance which require more heat. For that we need to know the specific heat of all the substances.

The substance which have the highest specific heat, will require more heat.

The specific heat of the given substances are:

Silver = 11.3 kJ/mol

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Hence, the correct answer is silver.

7 0
2 years ago
4. Determine what elements are in the following compounds.
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3 years ago
How many milliliters are in one milligram?
mariarad [96]
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8 0
2 years ago
Consider the reaction
spayn [35]

Answer:

1- 0.04 M/s.

2- 0.16 M/s.

Explanation:

  • For the reaction: 4PH₃ → P₄ + 6H₂.

<em>The rate of the reaction = - d[PH₃]/4dt = d[P₄]/dt = d[H₂]/6dt.</em>

where, - d[PH₃]/dt is the rate of PH₃ changing "rate of disappearance of PH₃".

d[P₄]/dt is rate of P₄ changing "rate of appearance of P₄".

d[H₂]/dt is the rate of H₂ changing "rate of formation of H₂" (d[H₂]/dt = 0.24 M/s).

<u><em>(a) At what rate is P₄ changing?</em></u>

∵ The rate of the reaction = d[P₄]/dt = d[H₂]/6dt.

∴ <em>rate of P₄ changing = </em>d[P₄]/dt = d[H₂]/6dt = (0.240 M/s)/(6.0) = 0.04 M/s.

<u><em>(b) At what rate is PH</em></u>₃<u><em> changing?</em></u>

∵ The rate of the reaction = - d[PH₃]/4dt = d[H₂]/6dt.

∴ <em>rate of PH</em>₃<em> changing = </em>- d[PH₃]/dt = 4(d[H₂]/6dt) = (4)(0.240 M/s)/(6.0) = 0.16 M/s.

7 0
3 years ago
Read 2 more answers
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