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2 years ago

How many moles of disulfur decafluoride are present in 3.99 x 104 molecules of this compound? moles

Chemistry

1 answer:

arsen [322]2 years ago

6 0

<u>Answer:</u> The number of moles of disulfur decafluoride is $6.62\times 10^{-20}$

<u>Explanation:</u>

We are given:

Number of disulfur decafluoride molecules = $3.99\times 10^4$

According to mole concept:

$6.022\times 10^{23}$ number of molecules are contained in 1 mole of a compound.

So, $3.99\times 10^4$ number of molecules will be contained in = $\frac{1mol}{6.022\times 10^{23}}\times 3.99\times 10^{4}=6.62\times 10^{-20}mol$ of disulfur decafluoride.

Hence, the number of moles of disulfur decafluoride is $6.62\times 10^{-20}$

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If 34.7 g of AgNO₃ react with 28.6 g of H₂SO₄ according to this UNBALANCED equation below, how many grams of Ag₂SO₄ could be for

Luba_88 [7]

The number of grams of Ag2SO4 that could be formed is 31.8 grams

<u><em> calculation</em></u>

Balanced equation is as below

2 AgNO3 (aq) + H2SO4(aq) → Ag2SO4 (s) +2 HNO3 (aq)

Find the moles of each reactant by use of mole= mass/molar mass formula

that is moles of AgNO3= 34.7 g / 169.87 g/mol= 0.204 moles

moles of H2SO4 = 28.6 g/98 g/mol =0.292 moles

use the mole ratio to determine the moles of Ag2SO4

that is;

the mole ratio of AgNo3 : Ag2SO4 is 2:1 therefore the moles of Ag2SO4= 0.204 x1/2=0.102 moles

The moles ratio of H2SO4 : Ag2SO4 is 1:1 therefore the moles of Ag2SO4 = 0.292 moles

AgNO3 is the limiting reagent therefore the moles of Ag2SO4 = 0.102 moles

<h3> finally find the mass of Ag2SO4 by use of mass=mole x molar mass formula</h3>

that is 0.102 moles x 311.8 g/mol= 31.8 grams

3 0

3 years ago

The sugar in your kitchen has a molar mass of 342.3 g/mol. How many particles are present inside a sugar bowl if there are 250 g

Anastaziya [24]

Number of particles inside a sugar bowl = 4.4 x 10²³

<h3>Further explanation</h3>

Given

The molar mass of sugar = 342.3 g/mol

mass of sugar = 250 g

Required

Number of particles

Solution

1 mol = 6.02 x 10²³ particles

mol of sugar :

$\tt mol=\dfrac{mass}{molar~mass}$

mol = 250 g : 342.3 g/mol = 0.73 mol

Number of particles :

N = n x No

N = 0.73 x 6.02 x 10²³

N = 4.39 x 10²³ ≈ 4.4 x 10²³

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3 years ago

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AlladinOne [14]

Answer:

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Explanation:

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3 years ago

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Ksivusya [100]

Answer:

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Explanation:

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