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tiny-mole [99]
3 years ago
9

A coyote population has decreased by 168 over the past 3 years. The same number of coyotes were lost each year. Which division e

xpression gives the change in the coyote population each year? A) 168 3 B) 168 −3 C) −168 3 D) −168 −3
Mathematics
1 answer:
a_sh-v [17]3 years ago
6 0

Answer:

C, \frac{-168}{3}

Step-by-step explanation:

The number of coyotes is decreasing, which makes it negative, but you can't have a negative year, so the answer must be \frac{-168}{3}

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Help!!!! 20 points!!!!!!’
Gnoma [55]

Answer:

option c is the correct answer

first take y raised to the power 4 common then cancel its power by y raised to the power 3

you get your answer

3 0
3 years ago
HELP PLEASE!!<br> what is the solution of the system ? y=-8x-2 and y=-6x+4
Illusion [34]

Answer: -3

Since the both equal the same value we can combine the into -8x-2=-6x+4.

From there you can solve from whatever side you want, and the answer is -3.

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3 years ago
hurry I'm going to give free brainly to all who answer in 1 minute Q: If a person was born in 1962 how old would they be Q:16549
vladimir1956 [14]

Answer:

they would be 58 rn. and simp means someone who is willing to do anything for someone they like. they try to get with that person everyday and they like them alot.

Step-by-step explanation:

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8 0
3 years ago
Temperature transducers of a certain type are shipped in batches of 50. A sample of 58 batches was selected, and the number of t
andrew11 [14]

Answer:

a) X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

b) \frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

Step-by-step explanation:

Assuming this question: Temperature transducers of a certain type are shipped in batches of 50. A sample of 60 batches was selected, and the number of transducers in each batch not conforming to design specifications was determined, resulting in the following data:

2,1,2,4,0,1,3,2,0,5,3,3,1,3,2,4,7,0,2,3,

0,4,2,1,3,1,1,3,4,2,3,2,2,8,4,5,1,3,1,

5,0,2,3,2,1,0,6,4,2,1,6,0,3,3,3,6,2,3

(a) Determine frequencies and relative frequencies for the observed values of x = number of nonconforming transducers in a batch. (Round your relative frequencies to three decimal places.)

For this case first we order the dataset on increasing way and we got:

0 0 0 0 0 0 0

1 1 1 1 1 1 1 1 1 1

2 2 2 2  2 2 2 2 2 2 2 2 2

3 3 3 3 3 3 3 3 3 3 3 3  3 3

4 4 4 4 4 4

5 5 5

6 6 6

7

8

And we can construct the following table:

X        Freq.         Rel Freq.

__________________________

0           7              (7/58) = 0.121

1            10            (10/58)=0.172

2           13            (13/58) =0.224

3           14            (14/58)=0.241

4           6              (6/58)=0.103

5           3              (3/58)=0.052

6           3              (3/58)=0.052

7            1              (1/58) =0.017

8            1              (1/58)=0.017

_________________________

Total     58                 1.00

(b) What proportion of batches in the sample have at most four nonconforming transducers? (Round your answer to three decimal places.)

For this case this proportion would be:

\frac{7+10+13+14+6}{58}= \frac{50}{58}=0.862

4 0
3 years ago
Can someone please help me real quick? I’m running late to something important
Arada [10]

Answer:

35+2

Step-by-step explanation:

--=+

7 0
3 years ago
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