Complete question :
There are 575 fireworks to be shot off in a firework display every minute 12 new fireworks are shot off display write a verbal model and algebraic expression to represent the number of fireworks left to be shot off after t minutes.
Answer:
575 - 12t
Step-by-step explanation:
Given the following :
Total number of fireworks = 575
Number of shots per minute = 12
To calculate the number of fireworks left to be shot off after t minutes, The total number of fireworks already shot after the same time interval t in minutes, is first obtained, this is equivalent to (12*t). The result is then subtracted from the total number of fireworks to be shof off.
In algebraic terms
[total number of fireworks on display - (number of shots per minute × t)]
575 - 12t
Answer:
no
Step-by-step explanation:
no
Answer:
y = 3/5x + 5
Step-by-step explanation:
Slope-intercept form is y = mx + b where m is the slope (rise / run of the line) and b is y-intercept (y value of where the line intersects with the y-axis.
The line is rising up 3 and run to the right 5 and so it's slope is 3/5. The line intersects with the y-axis at a y value of 5 and so it's y-intercept is 5.
Therefore, your answer in slope-intercept form is y = 3/5x + 5.
2x -3y = 13
4x -y = -9
Multiply the second equation by -3 to make the coefficient of Y opposite the first equation.
4x -y = -9 x -3 = -12x + 3y = 27
Now add this to the first equation:
2x -12x = -10x
-3y +3y = 0
13 +27 = 40
Now you have :
-10x = 40
Divide each side by -10:
x = 40 / -10
x = -4
Now you have a value for x, replace that into the first equation and solve for y:
2(-4) - 3y = 13
-8 - 3y = 13
Add 8 to both sides:
-3y = 21
Divide both sides by -3:
y = 21/-3
y = -7
Now you have X = -4 and y = -7
(-4,-7)
Any points that are less than 6. So 5, 4, 3, 2, etc.
