Question

Factor completely 2x3y4 − 8x2y3 + 6xy2. 2(x3y4 − 4x2y3 + 3xy2) 2x(x2y4 − 4xy3 + 3y2) 2xy2(x2y2 − 4xy + 3) Prime

Answer 1

Answer:

The factorised term is:

$2xy^2(x^2y^2-4xy+3)$

Step-by-step explanation:

We are asked to factor the algebraic expression given as:

$2x^3y^4-8x^2y^3+6xy^2$

Now we will take out the variable which is common among all the terms and write the remaining expression in parantheses.

As $2xy^2$ is common among all the terms hence we write this term out of the parantheses and the remaining term inside it as to obtain then simplified expression as:

$2xy^2(x^2y^2-4xy+3)$