Answer:
Segment BF = 16 is true.
Step-by-step explanation:
Since, DE is parallel to BC, so DE will divide AB and AC proportionally.
Hence,
⇒ 
{Since, given that AE = 12, EC = 18 and AD = 6}
⇒ BD = 9.
Again, since, EF is parallel to AB, so EF will divide BC and AC proportionally.
Hence, 
⇒ 
{Since, given that AE = 12, EC = 18 and FC= 24}
⇒ BF = 16.
Therefore, segment BF = 16 is true. (Answer)
The proof is given below. Please go through it.
Step-by-step explanation:
To solve Δ ABC ≅ Δ DBC
From Δ ABC and Δ DBC
AB = BD (given)
AC = CD (given)
BC is common side
By SSS condition Δ ABC ≅ Δ DBC ( proved)
To solve Δ EHF ≅ Δ GHF
Δ EHF and Δ GHF
EH = HG ( given)
∠ EFH = ∠ GFH ( each angle is 90°)
HF is common side
By RHS condition
Δ EHF ≅ Δ GHF
7/8x²-3/4x - 5/8x²-1/4x+2
x²/4-x+2
Take a look at the picture i sent you
The answer is 46 for the perimeter
