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3 years ago

Solve this (6 + 5) + 65

Mathematics

2 answers:

Free_Kalibri [48]3 years ago

8 0

Answer:

(6+5) + 65

11 + 65

Step-by-step explanation: You have to do the semicolons first then do your problem

Paraphin [41]3 years ago

7 0

(6+5) + 65 =

11 + 65 =

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What to numbers can add up to 30 but multiply to 40?

saul85 [17]

<span>I believe your answer will be 10 & 20, because they BOTH are multiples of 40, ANNNNNNNNNNNNNNNNND when added together they equal 30! =D
I hope I helped! =D</span>

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3 years ago

Solve the following ODE's: c) y* - 9y' + 18y = t^2

Nastasia [14]

Answer:

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

Step-by-step explanation:

y''- 9 y' + 18 y = t²

solution of ordinary differential equation

using characteristics equation

m² - 9 m + 18 = 0

m² - 3 m - 6 m+ 18 = 0

(m-3)(m-6) = 0

m = 3,6

C.F. = $C_1e^{3t}+C_2e^{6t}$

now calculating P.I.

$P.I. = \frac{t^2}{D^2 - 9D +18}$

$P.I. = \dfrac{t^2}{(D-3)(D-6)}\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1-\frac{D}{6})^{-1}(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(1+\frac{D}{6}+\frac{D^2}{36}+....)(t^2)\\P.I. =\dfrac{1}{18}(1-\frac{D}{3})^{-1}(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(1+\frac{D}{3}+\frac{D^2}{9}+....)(t^2+\frac{2t}{6} + \frac{2}{36})\\P.I. =\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

hence the complete solution

y = C.F. + P.I.

y = $C_1e^{3t}+C_2e^{6t}$ + $\dfrac{1}{18}(t^2+\frac{2t}{6} + \frac{2}{36}+\frac{2t}{3}+\frac{2}{18}+\frac{2}{9})$

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3 years ago

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Debora [2.8K]

Answer:

1234567891011121314151617181920

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Assume that the heights of women are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. If

vesna_86 [32]

Answer:

<h2>The probability is 58 %.</h2>

Step-by-step explanation:

This problem belong to a normal distribution probability.

Mean = 63.6

Standard Deviation = 2.5.

We have to find the probability of a height greater than 63.0.

Due to the normal probability, we need to find the Z score first:

$Z=\frac{x-u}{o}$ ; where x is the height, u is the mean, and o is the standard deviation.

$Z=\frac{63-63.6}{2.5} \\Z= -0.24$

Once we have our Z score, we find the probability with the z-table (attached). So, for a z score of -0.24 we have a probability of 0.42.

But, the problem is asking for height greater than 63.0, this mean that we have to subtract 0.42 from 1, giving as result 0.58, which means a 58% of probability,

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3 years ago

Which two inequalities would you use to solve |2x – 4| < 5?

padilas [110]

A. because when you face an equality, you need to have a negative and positive answer.

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3 years ago