Answer:
The range of T is a subspace of W.
Step-by-step explanation:
we have T:V→W
This is a linear transformation from V to W
we are required to prove that the range of T is a subspace of W
0 is a vector in range , u and v are two vectors in range T
T = T(V) = {T(v)║v∈V}
{w∈W≡v∈V such that T(w) = V}
T(0) = T(0ⁿ)
0 is Zero in V
0ⁿ is zero vector in W
T(V) is not an empty subset of W
w₁, w₂ ∈ T(v)
(v₁, v₂ ∈V)
from here we have that
T(v₁) = w₁
T(v₂) = w₂
t(v₁) + t(v₂) = w₁+w₂
v₁,v₂∈V
v₁+v₂∈V
with a scalar ∝
T(∝v) = ∝T(v)
such that
T(∝v) ∈T(v)
so we have that T(v) is a subspace of W. The range of T is a subspace of W.
Answer:
read description
Step-by-step explanation:
y=-2(0)-4 ANSWER: y=-4
y=-2(1)-4 ANSWER: y=-6
y=-2(2)-4 ANSWER: y=-8
y=-2(3)-4 ANSWER: y=-10
The difference between the mixed numbers is equal to 5/6.
<h3>How to perform the subtraction between the two mixed numbers?</h3>
A mixed number is a number that is written as a whole number plus an improper fraction, here we want to compute:
(2 + 1/2) - (1 + 2/3)
We can group the whole numbers and the fractions, so we get:
(2 - 1) + (1/2 - 2/3)
Now we can simplify this so we get:
(2 - 1) + (1/2 - 2/3)
= 1 + (3/6 - 4/6) = 1 - 1/6 = 6/6 - 1/6 = 5/6
We conclude that the difference between the mixed numbers is equal to 5/6.
If you want to learn more about mixed numbers:
brainly.com/question/1746829
#SPJ1
112 <span>≥ b+128
First: You would subtract 128 on both sides of your sign
You would get: -16</span><span>≥ b <That is your answer
HOPE THIS HELPS! ^_^</span>
Hello,
When you have a polygon inscribed in a circle, the opposite angles are supplementary.
So we can start by saying that A + C = 180. Or x + 3x = 180. This gives us a value of 45 for x.
If we input that in for angle B, we get: 2(25) - 10 = 80.
If angle B = 80, then angle D must be 100, because the angles are supplementary.
Good luck,
MrEQ
