Answer:
This above a triangle that models our situation.
Explanation:
We have a two componens., since we have a western componet and southern component. One travel in a southern direction. and the other travel in the west.
Let the component that travel in the south be the length of a.
According to the problem, the westard component is half of that so let that length be a/2.
Now we must find the angle of the wind in the South.
This means that what is angle that is opposite of the western componet because that angle is the most southward angle. So know we apply the tan property.
Our side opposite of the angle we trying to find is the western component and the side adjacent to it is the southern component. Also remeber since western and Southern negative displacements, we have
Now we take the arctan or inverse tan of 1/2.
Answer:
to find the length just divide 7.50 and . 298
Answer:
D) The element is most likely from Group 6A or 7A and in period 2 or 3.
Explanation:
Electronegativity of an atom is the tendency of an atom to attract shared paired of electron to itself. Electronegativity increase across the period from left to right.The ability of an atom to attract electron to itself is electronegativity. Group 7A and 6A elements can easily attract atoms to itself so they are highly electronegative. The most electronegative element in the periodic table is fluorine.Group 6A and 7A is likely to have high electronegativity.
Electron affinity of an atom is the amount of energy release when an atom gains electron . Generally, when atom gains electron they become negatively charged. Group 6A and 7A elements have high electron affinity.
Ionization energy is the energy required to remove one or more electron from a neutral atom to form cations. ionization energy of group 7A and 6A are usually high because the energy required to remove these electron is usually very high . The elements in this groups usually gain electron easily so the energy to remove electron is very high.
Answer:
Point A is at higher potential than point B
Explanation:
Electrons are negatively charged - this means that they are attracted by positive charges and repelled by negative charges.
This also means that they tend to move in a direction opposite to the electric field lines (because electric field lines point away from a positive charge and toward a negative charge). So, they also tend to move from a point at lower potential to a point at higher potential.
In this problem, the electrons flow from point B to point A: therefore, point A must have higher potential than point B.
