Answer:
Given:
radius of the coil, R = 6 cm = 0.06 m
current in the coil, I = 2.65 A
Magnetic field at the center, B = 
Solution:
To find the number of turns, N, we use the given formula:
Therefore,
N = 22.74 = 23 turns (approx)
First establish the summation of the forces acting int the
ladder
Forces in the x direction Fx = 0 = force of friction (Ff) –
normal force in the wall(n2)
Forces in the y direction Fy =0 = normal force in floor (n1)
– (12*9.81) –( 60*9.81)
So n1 = 706.32 N
Since Ff = un1 = 0.28*706.32 = 197,77 N = n2
Torque balance along the bottom of the ladder = 0 = n2(4 m) –
(12*9.81*2.5 m) – (60*9.81 *x m)
X = 0.844 m
5/ 3 = h/ 0.844
H = 1.4 m can the 60 kg person climb berfore the ladder will
slip
April 8, 2024
The path of totality will cross Mexico, the USA, and Canada.
Answer:
Explanation:
Point P is situated outside sphere . For a non conducting sphere , electric field outside sphere is given by the relation
E = k Q / d²
15000 = 9 x 10⁹ x Q / .5²
Q = 416.67 X 10⁻⁹
Maximum field will be when d = r ( radius )
maximum E = kQ / r²
= 9 x 10⁹ x 416.67 X 10⁻⁹ / .3²
= 41667 N / C
