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Dennis_Churaev [7]
3 years ago
12

To titrate 45.00 milliliters of an unknown HCl sample, use 25.00 milliliters of a standard 0.2000 M NaOH titrant. What is the mo

larity of the HCl?
Chemistry
1 answer:
gtnhenbr [62]3 years ago
4 0
V ( HCl ) = 45.00 mL in liters : 45.00 / 1000 => 0.045 L

M ( HCl ) = ?

V ( NaOH ) = 25.00 / 1000 => 0.025 L 

M ( NaOH) = 0.2000 M

number of moles NaOH :

n = M x V = 0.2000 x 0.025 => 0.005 moles of NaOH

Mole ratio:

HCl + NaOH = NaCl + H2O

1 mole HCl ---------- 1 mole NaOH
? mole HCl ---------- 0.005 moles NaOH

moles HCl = 0.005 x 1 / 1

= 0.005 moles of HCl :

M ( HCl ) = n / V

M ( HCl ) = 0.005 / 0.045

= 0.1111 M

hope this helps!




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Answer:

89.34%

Explanation:

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n(H2O)= 0.2403

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n (Mg (OH)2) = 0.1202

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6.26/ 7.007 × 100

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In a fission reaction of U-235, there was a release of 9.20 × 1011 kJ of energy. What amount of mass in kilograms would have bee
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<span>e = mc^2 
 
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Plug in your numbers in the appropriate units.
</span><span>m=1.02 × 10^-5

pulled from another response, hope it helps</span>
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