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White raven [17]
3 years ago
5

What is normal body temperature in kelvins? Express your answer in kelvins using four significant figures.

Chemistry
1 answer:
nlexa [21]3 years ago
5 0

Answer : The normal body temperature in kelvins is, 310.2 K

Explanation :

The normal body temperature for human in degree Celsius is, 37^oC

Now we have to convert it into kelvin.

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273.15+^oC

where,

K = temperature in Kelvin

^oC = temperature in centigrade

As we are given the temperature,  37^oC

So,

K=273.15+^oC

K=273.15+(37^oC)

K=310.15\approx 310.2

Thus, the normal body temperature in kelvins is, 310.2 K

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using the following thermochemical equation, determine the amount of heat produced from the combustion of 24.3 g benzene (c6h6).
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the amount of heat produced from the combustion of 24.3 g benzene (c6h6) is ΔH = -976.5 kJ

There are two moles of benzene involved in the process (C6H6). Since the heat of this reaction is -6278 kJ, the burning of 2 moles of benzene will result in a heat loss of 6278 kJ. This reaction is exothermic.

Enthalpy, or the value of H, is a unit of measurement for heat that relies on the amount of matter present (number of moles).

Thus, 24.3 g of benzene contains:

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0.311 moles =x

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? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
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Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







</span>
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3 years ago
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fredd [130]

Answer:

<em>ii</em><em> </em><em>and</em><em> </em><em>iv</em><em> </em>

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