Answer:
There are 0.0305 calories in 0.128 joules
Explanation:
Given that,
Heat absorbed, Q = 0.128 J
We need to find the heat energy absorbed in calories.
We know that the relation between joules and calories is as follows :
1 calorie = 4.184 J
1 J = (1/4.184) J
So,
So, there are 0.0305 calories in 0.128 joules
Explanation:
Polarity is defined as the development of partial charges on the atoms of a molecule. In a water molecule, there are hydrogen and oxygen atoms.
Due to the difference in electronegativity of both hydrogen and oxygen atom there is development of partial positive charge on hydrogen atom and a partial negative charge on oxygen atom.
So, when bond between hydrogen and oxygen will break down then it will form hydrogen ions () and oxygen ions ().
Ion-dipole interactions are defined as the interactions that occur when an ion interacts with the dipole of a molecule.
When an electron is added to a neutral atom to convert it into a negative ion then the amount of change taking place in its energy is known as electron affinity.
So, oxygen atom has an affinity towards cations and hydrogen atom has an affinity for anions.
Thus, we can conclude that following interactions and processes contribute to the dissolution of ionic compounds in water:
1. Affinity of oxygen towards cations
2. Ion–dipole interactions
4. Hydration
6. Affinity of hydrogen towards anions
A. Light reflected from the object's surface must enter your eyes.
Q = mCΔT
Q is heat, m is mass, C is specific heat, and ΔT is change in temp
First, find how much energy you need to raise the heat to 100C, or the boiling point
Q = (50g)(4.18)(75 degrees) = 15675 J or 15.675 kJ
Then you need 40.7 kJ extra for each mole of water to evaporate it
If you have 50 grams of water and there are 18 grams per mol
50g / 18g = 2.8 moles x 40.7 = 113 kJ extra
15.675 + 113 kJ = 128.7 kJ required