Adding a(n) [Select] ' will slow down a chemical reaction.

When 8.30 mol Mg react with 13.5 mol HCI, what is the limiting reactant and how many moles of H2 can be formed?

vovikov84 [41]

6.75 moles of H₂

Explanation:

We have the following balanced chemical reaction:

Mg + 2 HCl → MgCl₂ + H₂

From the chemical reaction we deduce that if 1 mole of Mg is reating with 2 moles of HCl then 8.30 moles of Mg is reaction with 16.60 moles of HCl, quantity which is over our available 13.5 moles of HCl. The limiting reactant is HCl.

Knowing this we devise the following reasoning:

if 2 moles of HCl produces 1 mole of H₂

then 13.5 moles of HCl produces X moles of H₂

X = (13.5 × 1) / 2 = 6.75 moles of H₂

Learn more about:

balancing chemical equations

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4 0

3 years ago

A hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

kupik [55]

hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:

En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )

where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.

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6 0

2 years ago

How many moles of methane occupy a volume of 2.00 l at 50.0°c and 0.500 atm answer?

Sauron [17]

Data Given:
Pressure = P = 0.5 atm

Volume = V = 2.0 L

Temperature = T = 50 °C + 273 = 323 K

Moles = n = ?

Solution:
Let suppose the gas is acting Ideally, Then According to Ideal Gas Equation.

P V = n R T
Solving for n,
n = P V / R T

Putting Values,
n = (0.5 atm × 2.0 L) ÷ (0.0821 atm.L.mol⁻¹.K⁻¹ × 323 K)

n = 0.0377 mol

5 0

3 years ago

A person suffering from hyponatremia has a sodium ion concentration in the blood of 0.116 M and a total blood volume of 4.7 L .

klemol [59]

Explanation:

Normal moles of $Na^{+}$ = volume × normal concentration

= 4.7 × 0.139 = 0.6533 mol

Moles of $Na^{+}$ in hyponatremia blood = volume × hyponatremia concentration

= 4.7 × 0.116 = 0.5452 mol

Moles of NaCl to be added = moles of extra $Na^{+}$ needed

= 0.6533 mol - 0.5452 mol = 0.1081 mol

Mass of NaCl = moles × molar mass of NaCl

= 0.1081 mol × 58.443

= 6.317g

= 6.32 g (approx)

Thus, we can conclude that mass of sodium chloride would need to be added to the blood is 6.32 g.

3 0

3 years ago

What properties are attributed to a solid with the type of bonding represented in the picture?

Elanso [62]

B it is a cold melting point

6 0

3 years ago