Calculate the volume of carbon dioxide at room temperature and pressure that can be obtained from 30.0g of glucose.

Where in the laboratory is long, unrestrained hair most likely to be a safety concern? near an open flame close to a fume hood n

zimovet [89]

Answer:

near an open flame

Explanation:

if your hair is not tied back near open flames in combination with most hair care products it would turn you into a living torch

7 0

2 years ago

the rate of a reaction increases when a catalyst has been added to the reaction mixture. the catalyst a) increases the kinetic e

Karolina [17]

The rate of the reaction increases when a catalyst has been added to the reaction mixture by e) providing a new mechanism for the reaction to procced by

Catalyst, in chemistry, a substance that speeds up a reaction without itself being consumed. Enzymes are natural catalysts responsible for many important biochemical reactions.

Most solid catalysts are oxides, sulfides, halides of metals or metallic elements, and metalloid elements boron, aluminum and silicon. Gas and liquid catalysts are usually used in pure form or in combination with suitable carriers or solvents. Solid catalysts are usually dispersed in another material known as a catalyst support.

Learn more about the catalyst in

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8 0

1 year ago

Question 24 (1 point)

aleksley [76]

Answer:

Explanation:

Idk

4 0

3 years ago

I Really Need Help:(

GarryVolchara [31]

Semi-conductor,brittle not malleable or ductile.

3 0

3 years ago

A student dissolves 6.2g of aniline c6h5nh2 in 350.ml of a solvent with a density of 1.04/gml . the student notices that the vol

Troyanec [42]

Answer : The correct answer for molarity = 0.19 $\frac{mol}{L}$ and Molality = 0.18 $\frac{mol}{Kg}$ .

Given : Mass of aniline = 6.2 g

Volume of solvent = 350 mL Density of solvent = 1.04 g/mL

1) Molarity : It is defined as number of moles of solute present in Litre of solution . It is expressed as :

$Molarity(M) = \frac{moles of solute(mole)}{volume of solution (L)}$ \

Molairty can be found in following steps :

Step 1 : To calculate mole :

Mole of solute can be calculate using mole formula :

$Mole of solute = \frac{given mass of solute (g)}{molar mass of solute\frac{g}{1 mol}}$

Molar mass of aniline (C₆H₅NH₂) = 93.13 $\frac{g}{1 mol}$

Mass of aniline = 6.2 g

Plugging values in mole formula :

$Mole = \frac{6.2 g}{93.13 \frac{g}{1 mol}}$

Mole = 0.0665 mol

Step 2 : To find volume of solution

Volume of solution = volume of solute + volume of solution

Since addition of aniline does not change final volume , so volume of solvent = volume of solution. Since volume is given in mL , so it need to be converted to L .

1 L = 1000mL

$Volume of solution = \frac{350 mL}{1000mL} * 1 L$