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xxTIMURxx [149]
2 years ago
8

Calculate the volume of carbon dioxide at room temperature and pressure that can be obtained from 30.0g of glucose.​

Chemistry
1 answer:
ella [17]2 years ago
3 0

Answer:

2 C2H6 +7 O2=====> 4 CO2 + 6 H2O.

Explanation:

Think this is it

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Nuclear energy is currently used in which three kinds of vehicles?
qaws [65]

Nuclear power plants produce little to no greenhouse gas.

Nuclear power plants produce a large amount of energy for a small mass of fuel.

8 0
3 years ago
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Is fluorine a nonmetal or metal?
Ratling [72]

Answer:

Nonmetal...

Explanation:

T^T

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2 years ago
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If I had 3.50 x 10 24molecules of Cl2 gas, how many grams is this?
Zinaida [17]

Answer:

412 g Cl₂

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 3.50 × 10²⁴ molecules Cl₂

[Solve] grams Cl₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

[PT] Molar Mass of Cl - 35.45 g/mol

Molar Mass of Cl₂ - 2(35.45) = 70.9 g/mol

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 3.50 \cdot 10^{24} \ molecules \ Cl_2(\frac{1 \ mol \ Cl_2}{6.022 \cdot 10^{23} \ molecules \ Cl_2})(\frac{70.9 \ g \ Cl_2}{1 \ mol \ Cl_2})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 412.072 \ g \ Cl_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

412.072 g Cl₂ ≈ 412 g Cl₂

5 0
3 years ago
Best answer will be tagged brainliest.... no spamming pliz​
grin007 [14]

\huge \mathcal \fcolorbox{cyan}{black}{ \blue{AnSweR}}

A. Chloride ions (CI)

\large{ \green{ \bold{ \underline{ \underline{ \overline{ \overline{ \pink{hope \: this \: helps \: you \: \: ✌}}}}}}}}

5 0
3 years ago
Question 10 OT 20
Airida [17]

Answer:

B) is reduced.

Explanation:

Oxidation:

Oxidation involve the removal of electrons and oxidation state of atom of an element is increased.

Reduction:

Reduction involve the gain of electron and oxidation number is decreased.

Consider the following reactions.

4KI + 2CuCl₂  →   2CuI  + I₂  + 4KCl

the oxidation state of copper is changed from +2 to +1 so copper get reduced and it is oxidizing agent.

CO + H₂O   →  CO₂ + H₂

the oxidation state of carbon is +2 on reactant  side and on product side it becomes  +4 so carbon get oxidized and it is reducing gent.

Oxidizing agents:

Oxidizing agents oxidize the other elements and itself gets reduced.

Reducing agents:

Reducing agents reduced the other element are it self gets oxidized.

8 0
3 years ago
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