2 years ago

Calculate the volume of carbon dioxide at room temperature and pressure that can be obtained from 30.0g of glucose.

Chemistry

1 answer:

ella [17]2 years ago

3 0

Answer:

2 C2H6 +7 O2=====> 4 CO2 + 6 H2O.

Explanation:

Think this is it

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How many molecules of ethane are present in 64.28 liters of ethane gas (C2H6) at STP

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Answer : The molecule of ethane present in 64.28 L of ethane gas at STP is, $17.277\times 10^{23}$ molecule.

Solution :

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22.4 L volume of ethane present in 1 mole of ethane gas

64.28 L volume of ethane present in $\frac{64.28L}{22.4L}\times 1mole=2.869moles$ of ethane gas

And, as we know that

1 mole of ethane molecule contains $6.022\times 10^{23}$ molecules of ethane

2.869 moles of ethane molecule contains $2.869\times 6.022\times 10^{23}=17.277\times 10^{23}$ molecules of ethane

Therefore, the molecule of ethane present in 64.28 L of ethane gas at STP is, $17.277\times 10^{23}$ molecule.

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Read 2 more answers

Calculate the volume of carbon dioxide at room temperature and pressure that can be obtained from 30.0g of glucose.​

Calculate the volume of carbon dioxide at room temperature and pressure that can be obtained from 30.0g of glucose.