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Marina86 [1]
3 years ago
5

20 points please help

Mathematics
2 answers:
sdas [7]3 years ago
7 0
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Just find the coordinate where the y value is not 3 times the x value

In this case, it would be (0 , 1)

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Mars2501 [29]3 years ago
3 0

Answer:

\large \boxed{\mathrm{(0, 1) \ and \ (3,27)}}

Step-by-step explanation:

The points (1, 3) and (2, 6) lie on the line y = 3x.

The points (0, 1) and (3, 27) do not lie on the line y = 3x.

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Number two and explain
bekas [8.4K]

Step-by-step explanation:

It should be tan(k)=32/40

Tangent is opposite/adjacent and 24/32 is adjacent/opposite which is not a trig function.

4 0
3 years ago
1. Let L be a list of numbers in non-decreasing order, and x be a given number. Describe an algorithm that counts the number of
e-lub [12.9K]

Answer:

Algorithm

Start

Int n // To represent the number of array

Input n

Int countsearch = 0

float search

Float [] numbers // To represent an array of non decreasing number

// Input array elements but first Initialise a counter element

Int count = 0, digit

Do

// Check if element to be inserted is the first element

If(count == 0) Then

Input numbers[count]

Else

lbl: Input digit

If(digit > numbers[count-1]) then

numbers[count] = digit

Else

Output "Number must be greater than the previous number"

Goto lbl

Endif

Endif

count = count + 1

While(count<n)

count = 0

// Input element to count

input search

// Begin searching and counting

Do

if(numbers [count] == search)

countsearch = countsearch+1;

End if

While (count < n)

Output count

Program to illustrate the above

// Written in C++

// Comments are used for explanatory purpose

#include<iostream>

using namespace std;

int main()

{

// Variable declaration

float [] numbers;

int n, count;

float num, searchdigit;

cout<<"Number of array elements: ";

cin>> n;

// Enter array element

for(int I = 0; I<n;I++)

{

if(I == 0)

{

cin>>numbers [0]

}

else

{

lbl: cin>>num;

if(num >= numbers [I])

{

numbers [I] = num;

}

else

{

goto lbl;

}

}

// Search for a particular number

int search;

cin>>searchdigit;

for(int I = 0; I<n; I++)

{

if(numbers[I] == searchdigit

search++

}

}

// Print result

cout<<search;

return 0;

}

8 0
3 years ago
I really need help please
Hatshy [7]
(-6,-4)
the point D can shift left 2 units which would be at that point
8 0
3 years ago
Pllllllllsssssss help 25 points
kipiarov [429]

Answer:

just buy a phone with a screen protector

Step-by-step explanation:

5 0
3 years ago
a rectangular room is 2meters longer than it is wide, and it's perimeter is 24 meters. find the dimension of the room​
asambeis [7]

2l + 2(l+2)=24 \\2l +2l+4=24 \\4l=20 \\\boxed{l=5}

Length of the room is 5 m and width is 5 + 2 = 7 m.

Hope this helps.

r3t40

5 0
4 years ago
Read 2 more answers
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