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Marina86 [1]
3 years ago
5

20 points please help

Mathematics
2 answers:
sdas [7]3 years ago
7 0
<h3>♫ - - - - - - - - - - - - - - - ~<u>Hello There</u>!~ - - - - - - - - - - - - - - - ♫</h3>

➷ Just find the coordinate where the y value is not 3 times the x value

In this case, it would be (0 , 1)

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

Mars2501 [29]3 years ago
3 0

Answer:

\large \boxed{\mathrm{(0, 1) \ and \ (3,27)}}

Step-by-step explanation:

The points (1, 3) and (2, 6) lie on the line y = 3x.

The points (0, 1) and (3, 27) do not lie on the line y = 3x.

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-4x + 2(5x - 6) = 6(x - 2)
Ugo [173]

Answer:

Sorry but this equation gives me 6x-12=6x-12

Step-by-step explanation:

Hope u don't mind me asking but have u tried it out yet and what did you get???

Is that a negative b4 4x??

8 0
3 years ago
What is the area of this figure?
yKpoI14uk [10]

Answer:

I might be 560

Step-by-step explanation:

35x16

8 0
3 years ago
Let f(x) = x2 - 81. Find f-1(x).
dusya [7]
This is equivalent to finding a function g in which g(x^2-81)=x.

We simply reverse the actions of the initial function by adding 81 back and taking the square root.  Therefore, f^{-1}(x)=\sqrt{x+81}.
7 0
3 years ago
The 5th term in a geometric sequence is 160. The 7th term is 40. What are possible values of the 6th term of the sequence?
omeli [17]

Answer:

C. The 6th term is positive/negative 80

Step-by-step explanation:

Given

Geometric Progression

T_5 = 160

T_7 = 40

Required

T_6

To get the 6th term of the progression, first we need to solve for the first term and the common ratio of the progression;

To solve the common ratio;

Divide the 7th term by the 5th term; This gives

\frac{T_7}{T_5} = \frac{40}{160}

Divide the numerator and the denominator of the fraction by 40

\frac{T_7}{T_5} = \frac{1}{4} ----- equation 1

Recall that the formula of a GP is

T_n = a r^{n-1}

Where n is the nth term

So,

T_7 = a r^{6}

T_5 = a r^{4}

Substitute the above expression in equation 1

\frac{T_7}{T_5} = \frac{1}{4}  becomes

\frac{ar^6}{ar^4} = \frac{1}{4}

r^2 = \frac{1}{4}

Square root both sides

r = \sqrt{\frac{1}{4}}

r = ±\frac{1}{2}

Next, is to solve for the first term;

Using T_5 = a r^{4}

By substituting 160 for T5 and ±\frac{1}{2} for r;

We get

160 = a \frac{1}{2}^{4}

160 = a \frac{1}{16}

Multiply through by 16

16 * 160 = a \frac{1}{16} * 16

16 * 160 = a

2560 = a

Now, we can easily solve for the 6th term

Recall that the formula of a GP is

T_n = a r^{n-1}

Here, n = 6;

T_6 = a r^{6-1}

T_6 = a r^5

T_6 = 2560 r^5

r = ±\frac{1}{2}

So,

T_6 = 2560( \frac{1}{2}^5) or T_6 = 2560( \frac{-1}{2}^5)

T_6 = 2560( \frac{1}{32}) or T_6 = 2560( \frac{-1}{32})

T_6 = 80 or T_6 = -80

T_6 =±80

Hence, the 6th term is positive/negative 80

8 0
3 years ago
The difference of two numbers is 10. Their sum is 23. Find the numbers.
Vika [28.1K]

Answer:

I don't knowektjtejejrjr

4 0
3 years ago
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