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2 years ago

I want to make sure that my work is correct so if possible can someone look at it and tell me if i got the table part correct?

Mathematics

1 answer:

Ilya [14]2 years ago

4 0

The one about the decreasing interval is incorrect, the graph does not decrease from -2 to infinity, that would be increasing because the slope of the line is positive. The for the decreasing interval, it would be negative infinity to -2 because that part of the graph is going down.

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F(x) = x2 – 3x – 2 is shifted 4 units left. The result is g(x). What is g(x)?

Ray Of Light [21]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now... your expression is not in vertex form, that's ok... to do a horizontal shift to the left by 4 units, we can simply, add the C and B component to the "x" variable, C=4, B =1, that way the horizontal shift of C/B or 4/1 is just +4, giving us a horizontal shift to the left

$\bf f(x)=x^2-3x-2\impliedby \textit{let's change that for }f(1x+4)
\\\\\\
f(1x+4)=(1x+4)^2-3(1x+4)-2
\\\\\\
f(x+4)=x^2+8x+16-3x-12-2
\\\\\\
f(x+4)=x^2-5x+2\impliedby g(x)$

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3 years ago

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What is the product of 2p+q and -3q-6p+1

Arlecino [84]

Hey there,

The question is to find the product of the two factors (2p + q)(-3q - 6p + 1).

Now we just multiply across:

-6pq - 12p² + 2p -3q²- 6pq + q

Now we combine like terms:

-12p² - 3q² + 2p + q

So the result would be -12p² - 3q² + 2p + q.

Hope I helped,

Amna

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3 years ago

What is the distance from -2 to 0 ?

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B :)

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On her 21st birthday, Sydney deposited $400 in a new bank account that earns 3.7% interest compounded continuously. If there are

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$1,649.80

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Answer:

1/12

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b) 1 * 2 * 1 * 1 = 2 ways

This is one you should try.

Jim Kat Larry Kim

Jim Larry Kat Kim

You can't get another way.

There are 2 ways that Jim can arrive first and Kim Last shown in b

2/24 = 1/12

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