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3 years ago

Because the length cannot be negative the height of the plane is ___ miles.

Mathematics

1 answer:

Rudik [331]3 years ago

8 0

Look at all the steps above. They lead to a double solution. The symbol

$x=\pm 5$

means that $x$ can be either positive or negative 5. You can't accept negative values for lengths, so you're left with one option only.

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Alexis wants to make a paperweight at pottery class. He designs a pyramid-like mode l with a base area of 100 square centimeters

olga55 [171]

Answer:

$\frac{3}{2}$ g/cm²

Step-by-step explanation:

First, we need to find the volume of the prism. The volume of a square pyramid is V = Bh/3

B = 100 cm²

h = 6 cm

V = 100 cm² * 6 cm /3

V = 600 cm³ /3

V = 200 cm³

Next, we need to solve for the density based on the desired volume and mass.

m = mass = 300 g

V = volume

density = m/V

density = 300 g / 200 cm³

density = 3/2 g/cm³

The lowest possible density of the material to make the paperweight would be $\frac{3}{2}$ g/cm²

4 0

2 years ago

What is the missing reason in the proof?

Nookie1986 [14]

A) corresponding angle theorem

3 0

2 years ago

Mac earns 4927 bimonthly. how much does he earn per year

NISA [10]

118248
I think you need to do 2927x24

7 0

3 years ago

Read 2 more answers

"Tim's lawn is 20 meters by 30 meters. If Tim can mow 8 square meters of grass per minute, how long will it take him to mow the

frosja888 [35]

One hour and a half

5 0

2 years ago

You measure 20 turtles' weights, and find they have a mean weight of 45 ounces. Assume the population standard deviation is 11.5

Naily [24]

Answer: the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

Step-by-step explanation:

Formula for margin of error : $E=\dfrac{z^*\times (Population\ standard\ deviation)}{\sqrt{Sample\ size}}$

, where z* = Critical z-value.

Given: population standard deviation = 11.5 ounces

Sample size = 20

Z value for 90% confidence level = 1.645

margin of error (E) = $\dfrac{1.645\times11.5}{\sqrt{20}}$

$\approx4.23$

Hence, the maximal margin of error associated with a 90% confidence interval for the true population mean turtle weight = 4.23

3 0

2 years ago