Yes but In the bigger group each person would have less
Answer: 5 km walking and 30 km by bus
Step-by-step explanation:
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?
walking - 5km/h bus - 60km/h
distance walking - d₁ distance bus - d₂
time walking - t₁ time bus - t₂
d₁ + d₂ = 35
t₁ + t₂ = 1.5
v = d/t
vwalking = d₁/t₁
5 = d₁/t₁ ⇒ d₁ = 5t₁
vbus = d₂/t₂
60 = d₂/t₂ ⇒ d₂ = 60t₂
d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35
_________________________
5t₁ + 60t₂ = 35
t₁ + t₂ = 1.5 (*-5)
5t₁ + 60t₂ = 35
-5t₁ -5t₂ = -7.5 (+)
__________________________
55t₂ = 27.5
t₂ = 27.5/55 = 0.5 h
t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h
d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km
d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km
Answer:
6 ways.
There are one red, one blue and one green maker. So there are 3 markers they are in 3! = 3×2 = 6 ways.
Please mark brainliest! <3
Answer:
A
Step-by-step explanation:
b
b c
c d
d a
y esa ser la responsable respuesta
Answer: (0.465, 5.535)
Step-by-step explanation:
Formula to calculate the confidence interval (<em>when population standard deviation is unknown</em>) is given by :-

, where
= sample mean.
s= sample standard deviation.
n= Sample size.
= critical value
By considering the given information , we have
s=0.75
n= 9
Significance level =
[1-0.90=0.1]
By using students' t distribution -table , the critical value for 95% confidence level :

[Note: degree of freedom = n-1]
Now, the 90% confidence interval for the true mean weight of these Southern California avocados will be :




Hence, the required confidence interval =(0.465, 5.535)