2x+4y=0
substitute y with 0
2x+4(0)=0
solve the equation
2x+0=0
2x=0
divide by 2 on both sides
x=0
4x+8y=7
substitute y with 0
4x+8(0)=7
solve the equation
4x+0=7
4x=7
divide by 4 on both sides
x=7/4 or x=1 3/4 or x=1.75
3x-7y=-29
2x+2y=6
solve the bottom equation
3x-7y=-29
x=3-y
substitute for x
3(3-y)-7y=-29
solve the equation
y=19/5
now substitute for y
x=3-
solve for x
x=-4/5
the possible solution of the system is the ordered pair
(x,y)=()
Answer:
Thus, the two root of the given quadratic equation is 5.24 and 0.76 .
Step-by-step explanation:
Consider, the given Quadratic equation,
This can be written as ,
We have to solve using quadratic formula,
For a given quadratic equation we can find roots using,
...........(1)
Where, is the discriminant.
Here, a = 1 , b = -6 , c = 4
Substitute in (1) , we get,
and
We know (approx)
Substitute, we get,
(approx) and
(approx)
(approx) and
(approx)
Thus, the two root of the given quadratic equation is 5.24 and 0.76 .