<u>Answer:</u> The mass of cryolite produced in the reaction is 1181.8 g
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of aluminium oxide = 287 g
Molar mass of aluminium oxide = 102 g/mol
Putting values in equation 1, we get:

The given chemical reaction follows:

By Stoichiometry of the reaction:
1 mole of aluminium oxide produces 2 moles of cryolite
So, 2.814 moles of aluminium oxide will produce =
of cryolite
Now, calculating the mass of cryolite by using equation 1:
Moles of cryolite = 5.628 moles
Molar mass of cryolite = 210 g/mol
Putting values in equation 1, we get:

Hence, the mass of cryolite produced in the reaction is 1181.8 g