Burning Mg in the air and reacting with O2 forming a white powder of MnO
So the equation is going to be:
Mn + O2 ⇒ MnO (this equation is not conserved)
to make it equilibrium:
1- First we should put 2Mno to equal the O2 on both sides.
So it will be:
Mg + O2⇒ 2MgO
2- Second we should put 2Mn to equal the Mn on both sides.
2Mg + O2⇒ 2MgO (this equation is conserved)
After putting the physical states the final equilibrium equation is going to be:
Δ
2Mg(s) + O2(g)⇒ 2MgO(s)
24.305 g +28.08 g + 3(15.999 g)=100.382
219 g MgSIO3 (1 mole MGSIO3/100.382g)=2.181 mol MgSIO3
the answer is 2.18 mol MgSIO3
Answer : The mass of chlorine reacted with the phosphorus is, 53.25 grams.
Explanation :
First we have to calculate the moles of phosphorus.
Now we have to calculate the moles of 
The balanced chemical reaction is:
From the balanced chemical reaction, we conclude that
As, 2 moles of phosphorous react with 3 moles of
So, 0.5 moles of phosphorous react with 
moles of
Now we have to calculate the mass of
Molar mass of = 71 g/mol
Therefore, the mass of chlorine reacted with the phosphorus is, 53.25 grams.
Answer:
a physical change does not change the composition (what it's made of) as a chemical change would.
Kinetic energy=1/2*mass*velocity²
=1/2*291*49
=7129.5 Joules
