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frutty [35]
3 years ago
5

How is ice cream made???? Hurry plsss!!!

Chemistry
1 answer:
castortr0y [4]3 years ago
7 0

Answer:

Milk, cream, milk solids, sugars, modifying agents and flavourings are blended together in stainless steel vats.

The mix is homogenised to create a consistent texture.

The mix is pasteurised by heating at 82-85°C for 15 seconds then cooled to destroy bacteria.

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A balloon has a volume of 6.2 liters at 23.2 C. The balloon is then heated to a temperature of 144.0 C. What is the volume of th
Marina CMI [18]

Answer:

8.7 L

Explanation:

T2(V1/T1) = V2

417.15 K(6.2 L/296.45 K) = 8.7 L

Remember to almost always change celcius to kelvin. Also, this is part of Charle's Law (temp and volume are proportional, so if temp increaces so must the volume or vice versa). Lastly, Charle's Law has the formula of V1/T1 = V2/T2. I just rearranged it to go along with your problem. Hence, the T2(V1/T1) = V2

4 0
3 years ago
50 points!! Brainliest if correct!!
Luda [366]

The answer is C. The answer is C because if u increase the surface area, the more reactants u will get. and if u get more The reactants will move faster. Hoped that Helped!:-)

4 0
3 years ago
Calculate the pH of a buffer solution prepared by mixing 60.0 mL of 1.00 M lactic acid and 25.0 mL of 1.00 M sodium lactate.
marshall27 [118]
This problem could be solved easily using the Henderson-Hasselbach equation used for preparing buffer solutions. The equation is written below:

pH = pKa + log[(salt/acid]

Where salt represents the molarity of salt (sodium lactate), while acid is the molarity of acid (lactic acid). 

Moles of salt = 1 mol/L * 25 mL * 1 L/1000 mL = 0.025 moles salt
Moles of acid = 1 mol/L* 60 mL * 1 L/1000 mL = 0.06 moles acid
Total Volume = (25 mL + 60 mL)*(1 L/1000 mL) = 0.085 L

Molarity of salt = 0.025 mol/0.085 L = 0.29412 M
Molarity of acid = 0.06 mol/0.085 L = 0.70588 M

Thus,
pH = 3.86 + log(0.29412/0.70588)
pH = 3.48
4 0
3 years ago
HELP Me Please I will give 20 points
lisabon 2012 [21]

Answer:

1c

2a

3b

Explanation:

5 0
3 years ago
Read 2 more answers
32 gm of O2 to mole of O2
lana [24]

Molar mass of O2:-

\\ \rm\longmapsto 2(16u)=32g/mol

Now

\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \rm\longmapsto No\:of\;moles=\dfrac{32}{32}

\\ \rm\longmapsto No\:of\;moles=1mol

5 0
3 years ago
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