Solve system of equations using substitution:

1 answer:

5 0

1)
2x-y=16
-2y-x=-8
You need to solve on of the equations for x or y. I will solve the first equation for y.
2x-y=16
-y=-2x+16
y=+2x-16
Then you can substitute that y value for the y value in the second equation (2y-x=-8) can be written as 2(2x-16)-x=-8 since y=2x-16.
then you solve for x.
4x-32-x=-8
3x=24
x=8
therefore y=0 since 2(0)-8=-8
I will complete the second part of the question either in the comments or a new answer later when I have more time.

You might be interested in

Which values are solutions to the inequality below? √x ≤ 5

Romashka [77]

$\sqrt{x} \leq 5$

Find the real region for $\sqrt{x}$

$\sqrt{x}$ is real for $x \geq 0$

$= x \geq 0$

$\sqrt{x} \leq 5$

Square both sides:

$( \sqrt{x} )^2 \leq 5^2$

$5^2 = 5*5 =25$

Refine:

$x \leq 25$

Answer D

hope this helps!

5 0

3 years ago

Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was

Marizza181 [45]

Answer:

The raw score for his exam grade is 99.69.

Step-by-step explanation:

Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.

To find : What is the raw score for his exam grade?

Solution :

The formula use to find the z-score is

$z=\dfrac{x-\mu}{\sigma}$