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3 years ago

1. What controls the cell? 2. Calls can be many and _

1 answer:

4 0

Hey mate!
You stuck?

1.) The cell structure which controls the activities of the cell is the nucleus.

2.) Cells can be many ____ and _____ : Shapes; Sizes

Hope this helps! :)

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In a sample containing a mixture of only these gases at exactly one atmosphere pressure, the partial pressures of carbon dioxide

Black_prince [1.1K]

Answer:

Explanation:

The pressure of a gaseous mixture is equal to the sum of the partial pressures of the individual gases:

Σ $P_g_a_s$ $= P_1+P_2+P_3+...+P_n$

The prompt is trying to confuse you, but it actually tells us the pressure of the mixture to be 1 atm, but this can be converted to torr. Furthermore, we are informed only three gases are in the mixture: diatomic nitrogen, diatomic oxygen, and carbon dioxide:

$P_g_a_s=1 \ atm = 760 \ torr= P_N_2+P_O_2+P_C_O_2\\760 \ torr = 582.008 \ torr + P_O_2 \ + 0.285 \ torr$

Solve for Po2:

$P_o_2=(760-582.008-0.285) \ torr = 177.707 \ torr$

Thus, the partial pressure of diatomic oxygen is 177.707 torr.

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4 0

3 years ago

Coke is an impure form of carbon that is often used in the in- dustrial production of metals from their oxides. If a sample of c

steposvetlana [31]

Answer:

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

Explanation:

$2CuO+C\rightarrow 2Cu+CO_2$

1 Ton = 907185 grams

Mass of copper oxide = 1.0 Ton = 907185 grams

Moles of copper oxide = $\frac{907185 g}{79.55 g/mol}=11,403.95 moles$

According to reaction, 2 moles of copper oxide reacts with 1 mole of carbon.

Then 11403.95 moles of copper oxide will react with:

$\frac{1}{2}\times 11403.95 mol=5,701.98 mol$ of carbon

Mass of 5,701.98 moles of carbon:

$5,701.98 mol\times 12 g/mol=68,423.75 g$

Mass of coke = x

Mass of carbon = 68,423.75 g

Percentage of carbon in coke = 95%

$95\%=\frac{68,423.75 g}{x}\times 100$

$x=720,250.09 g=0.794 Ton$

The mass of coke needed to react completely with 1.0 ton of copper(II) oxide is 0.794 Ton.

3 0

3 years ago

1. How many milliliters of 10.0 M HNO 3 are needed to prepare 0.350 L of 0.400 M solution?

tatyana61 [14]

<h3>Answer:</h3>

14 milliliters

<h3>Explanation:</h3>

We are given;

10.0 M HNO₃

Prepared solution;

Volume of solution as 0.350 L
Molarity as 0.40 M

We are required to determine the initial volume of HNO₃

We are going to use the dilution formula;
The dilution formula is;

M₁V₁ = M₂V₂

Rearranging the formula;

V₁ = M₂V₂ ÷ M₁

=(0.40 M × 0.350 L) ÷ 10.0 M

= 0.014 L

But, 1 L = 1000 mL

Therefore,

Volume = 14 mL

Thus, the volume of 10.0 M HNO₃ is 14 mL

5 0

3 years ago

In a given population, which members are most likely to survive and produce offspring?

Aneli [31]

Answer:

Those individuals with advantageous traits are more likely to survive and reproduce. The survivors pass down these advantageous traits to their offspring.

Explanation:

8 0

2 years ago

What state does a maple tree enter during the winter?

Crank

D. dormancy is the correct answer

3 0

3 years ago

1. What controls the cell? 2. Calls can be many ____ and _____

1. What controls the cell? 2. Calls can be many and _