Your answer would come out to 18 electrons
Answer:
690 g IrI₃
Explanation:
To convert from moles to grams, you have to use the molar mass of the compound. The molar mass of IrI₃ is 572.92 g/mol. You use this as the unit converter in this equation:

Round to the lowest number of significant figures which is 2 to get 690 g IrI₃.
In carbohydrates the C:H:O is 1:2:1
The correct answer is 96.80 grams
Explanation:
The density of a substance shows the total mass the substance contains in 1 mL or 1 cm3 as density is calculated by using the formula D= M (mass) / V (volume). This implies, Iron contains 7.87 grams per milliliter. Moreover, this value and formula can be used to calculate the mass or volume of any other sample. The process to calculate the mass of an iron sample with a volume of 12.3 mL is shown below.
D = M ÷ V
7.87 mL = x ÷ 12.3 mL - x represents the missing value. Now find the value of x by solving the equation
x = 7.87 · 12.3
x = 96.80
This means a sample of 12.3 mL contains a mass of 96.80 grams. Also, you can know this value is correct because if you divide the mass by the value the density is the same (96.80 grams ÷ 12.3 mL = 7.87 g/mL)
Answer: The rate of appearance of
is 
Explanation:
Rate of a reaction is defined as the rate of change of concentration per unit time.
Thus for reaction:

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
![Rate=-\frac{1d[I^-]}{5dt}=+\frac{d[I_2]}{3dt}](https://tex.z-dn.net/?f=Rate%3D-%5Cfrac%7B1d%5BI%5E-%5D%7D%7B5dt%7D%3D%2B%5Cfrac%7Bd%5BI_2%5D%7D%7B3dt%7D)
Given:
= 
![+\frac{d[I_2]}{dt}=-\frac{3d[I^-]}{5dt}=-\frac{3}{5}\times 2.4\times 10^{-3}mol/Ls=1.44\times 10^{-3}mol/Ls](https://tex.z-dn.net/?f=%2B%5Cfrac%7Bd%5BI_2%5D%7D%7Bdt%7D%3D-%5Cfrac%7B3d%5BI%5E-%5D%7D%7B5dt%7D%3D-%5Cfrac%7B3%7D%7B5%7D%5Ctimes%202.4%5Ctimes%2010%5E%7B-3%7Dmol%2FLs%3D1.44%5Ctimes%2010%5E%7B-3%7Dmol%2FLs)
The rate of appearance of
is 