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IrinaK [193]
3 years ago
15

A ball of mass 0.2 kg is dropped from a height of 10 m. How much mechanical energy does it have right before it hits the ground?

(Assume there is no air resistance.) Acceleration due to gravity is g 9.8 m/s2.
(PLEASE HELP NEED ANSWERS ASAP)

Chemistry
1 answer:
lana [24]3 years ago
3 0

Answer:

19.6 J  

Step-by-step explanation:

Before the ball is dropped, it has a <em>potential energy </em>

PE = mgh

PE = 0.2 × 10 × 9.8

PE = 19.6 J

Just before the ball hits the ground, the potential energy has been converted into kinetic (<em>mechanical</em>) energy.

KE = 19.6 J

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At 23.0 o C the vapor pressure of water is 21.1 mmHg. (This can be found on a vapor pressure table.)

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Convert the corrected pressure to atmospheres.

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n = (0.975 atm) (.193 L) / (.0821 L atm / mol K) (298 K)

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Use the number of moles and the molecular weight of oxygen to find out how many grams of oxygen were collected.

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