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adoni [48]
3 years ago
7

If you change the 2 in front of 2O2 to a 3, what will be the change in the results on the right side of the equation? (1 point)

Chemistry
1 answer:
Simora [160]3 years ago
3 0

Answer:

There is an extra O2 molecule left over

Explanation:

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Which of these figures probably shows a sugar solution containing a small amount of sugar dissolved in water
Vesnalui [34]

Answer:

The correct answer is Sugar has a greater solubility than sand.

Sugar will easily dissolve in water because it has a lower density than sand, therefore it has a greater solubility.

8 0
3 years ago
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Determine the pH of a 2.8 ×10−4 M solution<br> of Ca(OH)2.
shepuryov [24]

Answer:

pH = 10.75

Explanation:

To solve this problem, we must find the molarity of [OH⁻]. With the molarity we can find the pOH = -log[OH⁻]

Using the equation:

pH = 14 - pOH

We can find the pH of the solution.

The molarity of Ca(OH)₂ is 2.8x10⁻⁴M, as there are 2 moles of OH⁻ in 1 mole of Ca(OH)₂, the molarity of [OH⁻] is 2*2.8x10⁻⁴M = 5.6x10⁻⁴M

pOH is

pOH = -log 5.6x10⁻⁴M

pOH = 3.25

pH = 14-pOH

<h3>pH = 10.75</h3>
3 0
3 years ago
If an atom has 8 protons. How many electrons does it have? What is the atoms charge?
Juli2301 [7.4K]
The amount if protons is the same as the amount of electrons, so it would be 8. The charge is -2. Look at oxygen in the periodic table.
7 0
3 years ago
The ________ ion is represented by the electron configuration [ar]3d2.
Tresset [83]
The Ti 2+ ions is  represented  by  electron  configuration  (Ar)3d2. Titanium is in  atomic  number  22  and  its  electronic  configuration  is  (Ar)3d2 4s2.  Titanium loss two  electron that  is  4s2 electrons  hence the  electronic  configuration ( Ar)3d2.  4s2 is  the  valence electron  hence  it   the  one   which  is  lost  to  form  Ti2+
3 0
3 years ago
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Write the net ionic reaction that occurs upon the addition of hno3 to a solution which contains methylamine (ch3nh2) and methyla
ra1l [238]
Hello!

First, HNO₃ dissociates in the following way:

HNO₃(aq) → H⁺(aq) + NO₃⁻(aq)

Next, there is a neutralization reaction with Methylamine:

H⁺(aq) + CH₃NH₂(aq) → CH₃NH₃⁺(aq)

Finally, the formed methylammonium ion weakly dissociates in the following way:

CH₃NH₃⁺(aq) + H₂O(l)  ⇄ H₃O⁺(aq) + CH₃NH₂ (aq)

From this sequence of reactions, we can see that the resulting solution would be slightly more acidic than the initial one, as the buffer solution resists the addition of strong acid.

Have a nice day!
4 0
3 years ago
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