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ExtremeBDS [4]
3 years ago
8

List in order which digits are significant in the following numbers:

Chemistry
1 answer:
ozzi3 years ago
5 0

Answer:  see below

<u>Explanation:</u>

Zeros between the digit and decimal point are NOT significant.

Zeros between digits ARE significant.

a. 230 mL.              sf: 23

b. 0.00540 s          sf: 540

c. 1440                    sf: 144

d. 50 ℃                  sf: 5

e. 0.9405 g/cm3    sf: 9405

f. 700 jellybeans    sf: 7

g. 1.05 x 10⁶            sf: 105

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For a grating, how many lines per millimeter would be required for the first order diffraction line for λ = 400 nm to be observe
MA_775_DIABLO [31]

Answer:

For a grating, how many lines per millimeter would be required for the first order diffraction line for λ = 400 nm to be observed at a reflection angle of 5^{o} when the angle of incidence is  45^{o}?

<em>The number of lines per mm is 1985 lines </em>

Explanation:

A diffraction grating is used to separate a light source with multiple wavelengths into single wavelengths of different colors using the principle of diffraction.

Calculating for the spacing between the reflected surfaces

The spacing between the reflecting surfaces can be obtained using the relationship with the wavelength as shown below;

nA = d (sin i + sin r) ....................................1

where n is the order of diffraction = 1;

A is the wavelength = 400 nm

i is the angle of incidence = 45^{o}

r is the angle of refraction =  5^{o}

making d the subject formula from equation 1 we have;

d = \frac{nA}{sin i + sin r}...........................2

Now we substitute the given parameters into equation 2;

d = \frac{1(400 nm)}{(sin 45^{o}  ) + (sin 5^{o} )}

d = \frac{400 nm}{0.707 +0.087}

d = 503.7 nm

The spacing between reflecting surfaces is 503.7 nm

Calculating for the number of lines per millimeter

To calculate the number of spacing per millimeter we convert nanometer to millimeters, 1 mm =10^{6} and 1 line = 503.7 nm;

1 mm *\frac{1 line}{503.7 nm} *\frac{10^{6} }{mm}

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Therefore the number of lines per millimeter would be 1985 lines

6 0
3 years ago
How much H2O is produced when 20000 g of C2H2 burns completely? Answer in units of g.
IgorC [24]

Answer:

Explanation:

H  = 1

C = 12

O = 16

Acetylene, HC≡CH = 2+24 = 26

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In XS oxygen, one HC≡CH yields one H2O

26 g HC≡CH  ==> 18 g H2O

2000 g HC≡CH ==> 2000*18/26 g H2O =  1384.6154 g H2O

3 0
3 years ago
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