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Anna007 [38]
3 years ago
12

What evidence of a chemical reaction might you see in the following cases?

Chemistry
1 answer:
Ad libitum [116K]3 years ago
5 0
For bleaching a stain, there will be an identifiable odor and it will easily absorb colors and/or stains. Burning a match also has odor involved, but the smoke that is released is from a hot fire that is chemically produced by the formula to make the tip of the match.
You might be interested in
How many sulfur atoms are generated when 9.42 moles of H2S react according to the following equation: 2H2S+SO2→3S+2H2O
8_murik_8 [283]

Answer:

A) 8.51 × 10²⁴  

Explanation:

1. Gather all the information

            2H₂S + SO₂ ⟶ 3S + 2H₂O

n/mol:   9.42

2. Calculate the moles of S atoms

The molar ratio is 3 mol S:2 mol H₂S

\text{Moles of S} = \text{9.42 mol H$_{2}$S} \times \dfrac{\text{3 mol S }}{\text{2 mol H$_{2}$S }} = \text{14.13 mol S}

3. Calculate the atoms of S

\text{Atoms of S } = \text{14.13 mol S} \times \dfrac{6.022 \times 10^{23}\text{ S atoms}}{\text{1 mol S}} = \mathbf{8.51 \times 10^{24}}\textbf{ S atoms}

 

6 0
3 years ago
Read 2 more answers
What is the answer to this question
Stels [109]

Answer:

38 kg/m³

0.038 g/mL

Explanation:

Volume of a cube is the side length cubed.

V = s³

Given s = 0.65 m:

V = (0.65 m)³

V ≈ 0.275 m³

The mass is 10.5 kg.  The density is the mass divided by volume:

ρ = (10.5 kg) / (0.275 m³)

ρ ≈ 38 kg/m³

Or:

ρ ≈ 0.038 g/mL

4 0
3 years ago
One difference between mixtures and pure substances is that A) mixtures can be physically separated. B) mixtures are made of one
Alborosie
The answer your looking for is a)
 -please give me brainliest answer
5 0
3 years ago
Read 2 more answers
Plants are capable of using nitrogen directly from the atmosphere. True false
Nataly_w [17]
True I believe because plants require gases which they take from the air.
5 0
3 years ago
A liquid of density 1290 kg/m 3 flows steadily through a pipe of varying diameter and height. At Location 1 along the pipe, the
Gelneren [198K]

Answer:

114 kPa

Explanation:

By Bernoulli's equation when a fluid flows steadily through a pipe:

P + ρ*g*y + v² = constant in the pipe, where P is the pressure, ρ is the density of the fluid, g is the gravity acceleration (9.8 m/s²), y is the high, and v the velocity.

By the continuity equation, the liquid flow must be constant in the pipe, and then:

A1*v1 = A2*v2

Where A is the area, v is the velocity, 1 is the point 1, and 2 the point 2 in the pipe. The are is the circle area: π*(d/2)². So:

π*(0.105/2)²*9.91 = π*(0.167/2)²*v2

0.007v2 = 0.027

v2 = 3.9 m/s

Then:

P1 + ρ*g*y1 + v1² = P2 + ρ*g*y2 + v2²

ρ*g*y1 - ρ*g*y2 + v1² - v2² = P2 - P1

ρ*g*Δy + v1² - v2² = ΔP

ΔP = 1290*9.8*9.01 + 9.91² - 3.9²

ΔP = 113,987.42 Pa

ΔP = 114 kPa

8 0
3 years ago
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