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Mariana [72]
3 years ago
15

How is a compound different from a mixture?

Chemistry
2 answers:
ANTONII [103]3 years ago
8 0

Answer:

<u>Mixture</u> is <u>composed of molecules</u> <em>of</em> different types. A <u>compound</u> can <em><u>only</u></em> be separated through <u>chemical means</u>.

Marrrta [24]3 years ago
6 0

Answer: a compound is a chemically made or chemically bonded where as a mixture is just something added like a smoothie

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6. Macromolecules represent which level of organization in the body?
hodyreva [135]

Answer:

Chemical

Explanation:

Macromolecules are part of the chemical components of cells. For example, DNA, proteins, and lipids.

Cells of similar types/function form tissues. Different types of tissues interact together to form organs. Organs form a common function.

6 0
3 years ago
Gizmo Student Exploration: Periodic Trends awner key, Please I need help with this as soon as possible! I have attached what I h
Vlad [161]

Answer:

I cant see it

Explanation:

6 0
3 years ago
The element californium (cf) sells for $1000 per µg. assuming 6.02 x 1023 atoms of cf have a mass of 251 grams, how many atoms o
saveliy_v [14]

Answer:- 2.40*10^1^0atoms

Solution:- It is a simple unit conversion problem. We could solve this using dimensional analysis.

We know that, 1 US dollar = 100 cents

1 cent  = 1 US penny

So, 1 US dollar = 100 US pennies

1g=10^6\mu g

Let's make the set up starting with 1 penny as:

1penny(\frac{$1}{100pennies})(\frac{1\mu g}{$1000})(\frac{1g}{10^6\mu g})(\frac{6.02*10^2^3atoms}{251g})

= 2.40*10^1^0atoms

Therefore, we can bye 2.40*10^1^0atoms of Cf in one US penny.

3 0
3 years ago
A) Calculate the average density of the following object (assume it is a perfect sphere). SHOW ALL YOUR WORK (formulas used, num
-BARSIC- [3]

Answers:

A) 2040 kg/m³; B) 58 600 km

Explanation:

A) Density

V = \frac{ 4}{3 }\pi r^{3} = \frac{ 4}{3 }\pi\times (\text{1150 km})^{3} = 6.37 \times 10^{9} \text{ km}^{3}

\text{Density} = \frac{\text{mass}}{\text{volume}} = \frac{1.3\times 10^{22} \text{ kg} }{6.37 \times 10^{9} \text{ km}^{3}}\times (\frac{\text{1 km}}{\text{1000 m}})^{3} = \text{2040 kg/m}^{3}

<em>B) Radius</em>

\text{Volume} = \frac{\text{mass}}{\text{density}} = \frac{5.68\times 10^{26} \text{ kg} }{687 \text{ kg/m}^{3} }= 8.268 \times 10^{23} \text{ m}^{3}

V = \frac{ 4}{3 }\pi r^{3}

r^{3} = \frac{3V }{4 \pi }\

r= \sqrt [3]{ \frac{3V }{4 \pi } }

r= \sqrt [3]{ \frac{3\times 8.268 \times 10^{23} \text{ m}^{3}}{4 \pi } }= \sqrt [3]{ 1.974 \times 10^{23} \text{ m}^{3}}= 5.82 \times 10^{7} \text{ m}=\text{58 200 km}

3 0
3 years ago
Why does magma in the mantle rise through the crust above it
Natali5045456 [20]
Currents from the lava
4 0
3 years ago
Read 2 more answers
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