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Simora [160]
3 years ago
7

Which of the following chemical reactions is the only reaction shown that would be predicted to occur based on the activity seri

es?
A. Ca + BaBr2- Ba + CaBr2
B. Mn + NiBr2 - Ni + MnBr2
C. Au + PtBr - Pt + AuBr
D. Zn + MgBr2 Mg + ZnBr2
Chemistry
1 answer:
Novosadov [1.4K]3 years ago
7 0

B. Mn + NiBr₂  →  Ni + MnBr₂

Explanation:

The reaction that can be predicted of all is Mn + NiBr₂  →  Ni + MnBr₂.

The activity series is used to predict the products of single displacement reactions.

The series ranks metals in order of their reactivity. Those higher up in the series are highly reactive metals. Those at the bottom are slightly to non-reactive metals.

For a single displacement reaction to occur, a metal higher up in the activity series displaces one that is lower in the series.

  Reaction A will not occur, Ba is higher in the series

  Reaction C will not occur, Pt and Au are unreactive

  Reaction D will not occur as Zn is lower in the series

Mn is higher in the reactivity series and it will displace Ni from the solution.

Learn more:

Synthesis reaction brainly.com/question/4216541

#learnwithBrainly

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H2(g) + Br2(l) ⇄ 2HBr(g) Kc = 4.8 × 108
elena-14-01-66 [18.8K]

Answer:

  • 1.5 × 10⁻⁹M

Explanation:

<u>1. Equilibrium equation</u>

  • H₂(g) + Br₂(l) ⇄ 2HBr(g)

<u>2. Equilibrium constant</u>

The liquid substances do not appear in the expression of the equilibrium constant.

    k_c=\dfrac{[HBr(g)]^2}{[H_2]}=4.8\times 10^8M

<u>3. ICE table.</u>

Write the initial, change, equilibrium table:

Molar concentrations:

         H₂(g) + Br₂(l) ⇄ 2HBr(g)

I          0.400                   0

C           - x                      +2x

E         0.400 - x              2x

<u>4. Substitute into the expression of the equilibrium constant</u>

     4.8\times 10^8=\dfrac{(2x)^2}{0.400-x}

<u>5. Solve the quadratic equation</u>

  • 192,000,000 - 480,000,000x = 4x²
  • x² + 120,000,000x - 48,000,000 = 0

Use the quadratic formula:

       

x=\dfrac{-120,000,00\pm\sqrt{(120,000,000)^2-4(1)(-48,000,000}}{2(1)}

The only valid solution is x = 0.39999999851M

Thus, the final concentration of H₂(g) is 0.400 - 0.39999999851 ≈ 0.00000000149 ≈ 1.5 × 10⁻⁹M

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How fast is an electron travelling If it has a wavelength of 8.20 km?
Lemur [1.5K]

The electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

<h3>How to calculate velocity of an electron?</h3>

The velocity at which an electron travels can be calculated using the following formula:

λ = h/mv

Where;

  • H = Planck's constant
  • m = mass of electron
  • v = velocity of electron
  • λ = wavelength

  • Planck's constant (h) = 6.626 × 10−³⁴ J⋅s.
  • mass of electron (m) = 9.109 × 10−³¹ kg
  • wavelength = 8200m

8200 = 6.626×10−³⁴ / 9.109 × 10−³¹V

8200 = 7.3 × 10-⁴V

V = 8200 ÷ 7.3 × 10-⁴

V = 1.123 × 10⁷m/s

Therefore, the electron is travelling with a velocity of 1.123 × 10⁷m/s if it has a wavelength of 8.20 km.

Learn more about velocity at: brainly.com/question/13171879

#SPJ1

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Angelina_Jolie [31]

YES IT'S @LL CORRECT

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