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Simora [160]
2 years ago
7

Which of the following chemical reactions is the only reaction shown that would be predicted to occur based on the activity seri

es?
A. Ca + BaBr2- Ba + CaBr2
B. Mn + NiBr2 - Ni + MnBr2
C. Au + PtBr - Pt + AuBr
D. Zn + MgBr2 Mg + ZnBr2
Chemistry
1 answer:
Novosadov [1.4K]2 years ago
7 0

B. Mn + NiBr₂  →  Ni + MnBr₂

Explanation:

The reaction that can be predicted of all is Mn + NiBr₂  →  Ni + MnBr₂.

The activity series is used to predict the products of single displacement reactions.

The series ranks metals in order of their reactivity. Those higher up in the series are highly reactive metals. Those at the bottom are slightly to non-reactive metals.

For a single displacement reaction to occur, a metal higher up in the activity series displaces one that is lower in the series.

  Reaction A will not occur, Ba is higher in the series

  Reaction C will not occur, Pt and Au are unreactive

  Reaction D will not occur as Zn is lower in the series

Mn is higher in the reactivity series and it will displace Ni from the solution.

Learn more:

Synthesis reaction brainly.com/question/4216541

#learnwithBrainly

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Answer:

Q = 0.50

No

Left

Explanation:

At a generic reversible equation

aA + bB ⇄ cC + dD

The reaction coefficient (Q) is the ratio of the substances concentrations:

Q = \frac{[C]^c*[D]^d}{[A]^a*[B]^b}

Solids and liquid water are not considered in this calculus.

When the reaction achieves equilibrium (concentrations are constant), the Q value is named as Kc, which is the equilibrium constant of the reaction. If Q > Kc, it indicates that the concentration of the products is higher, so, the reaction must progress to the left and form more reactants; if Q < Kc, than the concentrations of the reactants, are higher, so, the reaction progress to the right.

In this case:

Q = \frac{[NO_2]^2}{[N_2O_4]}

Q = \frac{0.50^2}{0.50}

Q = 0.50

So, Q > Kc, the reaction is not at equilibrium and it progresses to the left.

6 0
3 years ago
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Answer:

It A(Ba3P2)

Explanation:

I took the test

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