Answer:
Ca(NO3)2(aq) —> Ca^2+(aq) + 2NO3^-(aq)
Explanation:
Ca(NO3)2 will dissociates in solution as follow:
Ca(NO3)2(aq) —> Ca^2+(aq) + NO3^-(aq)
The above equation can be balance as follow:
There are 2 atoms of NO3 on the left side and 1 atom on the right. It can be balance by putting 2 in front of NO3^- as shown below:
Ca(NO3)2(aq) —> Ca^2+(aq) + 2NO3^-(aq)
1) We know that rtp = number of moles × 24
= 0.25 × 24
= 6 dm³
Therefore the volume of 0.25 moles of gas at rtp is A) 6 dm³
3.1) Amount of Copper = 20 tonnes
Amount of pure copper from impure copper = 18 tonnes
Purity of copper = (Pure copper/ impure copper) × 100
= (18 / 20) × 100
= 18 × 5
= 90 %
Therefore the purity of copper is 90%
3.2) We know that oxygen has 8 protons and 8 neutrons, so the weight of oxygen molecule is 8 + 8 = 16 u
So, one mole of oxygen weighs 16 g, so 2 moles weigh 2 × 16 = 32 grams
But oxygen is diatomic so the weight is 32 × 2 = 64 grams
Therefore the weight of 2 moles of oxygen is 64 grams
3.3) Concentration of solution = Amount of solute/volume
= 4 moles/ 2 dm³
= 4 / 2
= 2 mol/dm³
Therefore the concentration of a solution containing 4 moles in 2 dm³ of solution is 2 mol/dm³
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Respuesta:
90.0 %
Explicación:
Paso 1: Escribir la ecuación química balanceada
N₂ + 3 H₂ ⇒ 2 NH₃
Paso 2: Calcular el rendimiento teórico de NH₃ a partir de 140 g de N₂
En la ecuación balanceada, participan de N₂: 1 mol × 28.01 g/mol = 28.01 g y de NH₃: 2 mol × 17.03 g/mol = 34.06 g.
140 g N₂ × 34.06 g NH₃ /28.01 g N₂ = 170 g NH₃
Paso 3: Calcular el rendimiento porcentual de NH₃
El rendimiento experimental de NH₃ es 153 g. Podemos calcular el rendimiento porcentual usando la siguiente fórmula.
R% = rendimiento experimental / rendimiento teórico × 100%
R% = 153 g / 170 g × 100% = 90.0 %
Having food in your stomach does not allow to keep alcohol from being absorbed but it does allow you to not get intoxicated as fast. this is a (FACT)!!!!
Explanation:
The mass of bromine is 79.904, and since there are two of them in the Calcium Bromide molecule, we'll multiply it by 2 to get 159.808. Dividing that by the full mass of the molecule then multiply it by 100 will give you the answer.
