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3 years ago

9

How do buffers work in the human body

1 answer:

Elodia [21]3 years ago

5 0

<span>How do buffers work in the human body?

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Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and Tr

ale4655 [162]

Solution :

For the reaction :

$\text{TrisH}^+ + H_2O \rightarrow \text{Trish}^- + H_3O^+$

we have

$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$

$=\frac{x^2}{0.02 -x}$

$=8.32 \times 10^{-9}$

Clearing $x$ , we have $x = 1.29 \times 10^{-5} \text{ moles of acid}$

So to reach $\text{pH} = 7.8 (\text{pOH}= 14-7.8=6.2)$ , one must have the $\text{OH}^-$ concentration of the :

$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$

So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.

$\text {n NaOH}=1.29 \times 10^{-5}+6.31 \times 10^{-7}$

$= 1.35 \times 10^{-5} \text{ moles}$

Volume NaOH $= 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \text{ mL}}{1 \text{ mol}} = 0.0135 \text{ mL}$

Tris mass $H^+ = 0.02 \text{ mol} \times 157.6 \text{ g/mol}=3.152 \text{ g}$

Now to prepare the said solution we must mix:

$3.152 \text{ g Tris H} + 0.0135 \text{ mL NaOH} \ 1 M$ gauge to 1000 mL with water.

3 0

3 years ago

What is the molecular formula of first 20 elements

attashe74 [19]

Answer:

H

He

Li

Be

B

C

N

O

F

Ne

Na

Mg

Al

Si

P

S

Cl

Ar

K

Ca

3 0

3 years ago

Si Units Worksheet. Use si units to complete

Keith_Richards [23]

$\\ \bull\tt\dashrightarrow 2000m=2km$

$\\ \bull\tt\dashrightarrow 9000mL=9L$

$\\ \bull\tt\dashrightarrow 6L=6000mL$

$\\ \bull\tt\dashrightarrow 6cm=60mm$

$\\ \bull\tt\dashrightarrow 1000m=1km$

$\\ \bull\tt\dashrightarrow 50mm=5cm$

$\\ \bull\tt\dashrightarrow 4L=4000mL$

$\\ \bull\tt\dashrightarrow 10000g=10kg$

$\\ \bull\tt\dashrightarrow 10000m=10km$

$\\ \bull\tt\dashrightarrow 4000g=4kg$

$\\ \bull\tt\dashrightarrow 9km=9000m$

$\\ \bull\tt\dashrightarrow 3kg=3000g$

$\\ \bull\tt\dashrightarrow 90mm=9cm$

$\\ \bull\tt\dashrightarrow 4km=4000m$

$\\ \bull\tt\dashrightarrow 2000g=2kg$

$\\ \bull\tt\dashrightarrow 400cm=4m$

$\\ \bull\tt\dashrightarrow 3km=3000m$

$\\ \bull\tt\dashrightarrow 2cm=20mm$

$\\ \bull\tt\dashrightarrow 9000g=9kg$

8 0

3 years ago

A block of metal has a mass of 0.0694 kg. It displaces 3.6 mL of water. What is it’s density in g/cm^3

Ivan

Answer:

19.28 g/cm^3 to the nearest hundredth.

Explanation:

The volume of water displaced = the volume of the metal.

density = mass / volume

0.0694 kg = 0.0694 * 1000

= 69.4 g.

Density = 69.4 / 3.6

= 19.28 g/cm^3.

4 0

3 years ago

A mutation occurs whenever one of the bases in DNA is changed. What letters represent those bases?

kenny6666 [7]

A: adenine
C: cytosine
g: guanine
t: thymine

5 0

2 years ago