Consider this equilibrium: COCl2(g) CO(g) + Cl2(g) Keq = 8.1 x 10-4. What is true for this system? [COCl2] < [CO][Cl2] [COCl2

Question

3 years ago

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] = [CO][Cl2] [COCl2] > [CO][Cl2]

2 answers:

const2013 [10] · Answer 1 · 2022-02-08T15:05:59+03:00

Answer is: [COCl₂] > [CO][Cl₂].

Chemical reaction: COCl₂(g) ⇄ CO(g) + Cl₂(g); Keq = 8.1 x 10⁻⁴.

Keq = [CO] · [Cl₂] / [COCl₂]; equilibrrium constant of chemical reaction.

[CO] · [Cl₂] / [COCl₂] = 0.00081.

Equilibrium product concentration is much more less than equilibrium concentration of reactant.

Zepler [3.9K] · Answer 2 · 2022-02-08T13:49:45+03:00

4 0

I'm pretty sure the answer here is C.