Complete question is;
A drop of water has a volume of approximately 7 × 10⁻² ml. How many water molecules does it contain? The density of water is 1.0 g/cm³.
This question will require us to first find the number of moles and then use avogadro's number to get the number of water molecules.
<em><u>Number of water molecules = 2.34 × 10²¹ molecules</u></em>
We are given;
Volume of water; V = 7 × 10⁻² ml
Density of water; ρ = 1 g/cm³ = 1 g/ml
Formula for mass is; m = ρV
m = 1 × 7 × 10⁻²
m = 7 × 10⁻² g
from online calculation, molar mass of water = 18.01 g/mol
Number of moles(n) = mass/molar mass
Thus;
n = (7 × 10⁻²)/18.01
n = 3.887 × 10⁻³ mol
from avogadro's number, we know that;
1 mol = 6.022 × 10²³ molecules
Thus,3.887 × 10⁻³ mol will give; 6.022 × 10²³ × 3.887 × 10⁻³ = 2.34 × 10²¹ molecules
Read more at; brainly.in/question/17990661
Answer :
(1) The frequency of photon is, 
(2) The energy of a single photon of this radiation is 
(3) The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol
Explanation : Given,
Wavelength of photon = 
(1 m = 100 cm)
(1) Now we have to calculate the frequency of photon.
Formula used :
where,
= frequency of photon
= wavelength of photon
c = speed of light = 
Now put all the given values in the above formula, we get:
The frequency of photon is,
(2) Now we have to calculate the energy of photon.
Formula used :
where,
= frequency of photon
h = Planck's constant = 
Now put all the given values in the above formula, we get:
The energy of a single photon of this radiation is
(3) Now we have to calculate the energy in J/mol.
The energy of an Avogadro's number of photons of this radiation is, 11.97 J/mol
Answer:
Yes, because the light was the manipulated variable
Explanation:
We use Charles's Law: V1/T1=V2/T2
Standard Temperature: 0 degree Celsius= 273K
333.0 degrees Celsius= 606K
Set up: (1.00L)/ (273K)= V2/ (606.0K)
⇒ V2= (1.00L)/ (273K)* (606.0K)= 2.22L
Hope this would help :))
