Answer:
Step-by-step explanation:
We want to write an exponential function that goes through the points (0, 20) and (6, 1280).
The standard exponential function is given by:
The point (0, 20) tells us that <em>y</em> = 20 when <em>x</em> = 0. Hence:
Simplify:
So, our exponential function is now:
Next, the point (6, 1280) tells us that <em>y</em> = 1280 when <em>x</em> = 6. Thus:
Solve for <em>b</em>. Divide both sides by 20:
Therefore:
![b=\sqrt[6]{64}=2](https://tex.z-dn.net/?f=b%3D%5Csqrt%5B6%5D%7B64%7D%3D2)
Hence, our function is:
Hello once again!
When you see a question like this, you need to find the equation of the straight line.
The formular used is y = mx + c
Where
m = slope
c = constant
First find the slope, since it's a straight line, any 2 coordinates can be used.
Now we need to substitude in the slope, and one of the coordinate you used to find the slope, to the formular to find the constant.
In this case i'm using the coordinate
(-2, 16)
y = mx + c
16 = -6(-2) + c
16 = 12 + c
c = 4
∴ The equation of the line is y = -6x + 4
The next step is to simply substitude in the x = 8 to the equation to find y.
y = -6(8) + 4
y = -48 + 4
y = -44
Answer:
7
/8
0.875
Step-by-step explanation:
The answer is 1/64 hope this helped!
X^2 - x - 42 = x^2 - 6x + 7x - 42 = x( x - 6) + 7(x - 6) = (x-6)(x+7);
The correct answer is a.
