Answer:
s = 38.7 m
Explanation:
First we calculate the distance covered during uniform motion of reaction time.
s₁ = vt
where,
s₁ = distance covered during uniform motion = ?
v = uniform speed = 11 m/s
t = time = 2.3 s
Therefore,
s₁ = (11 m/s)(2.3 s)
s₁ = 25.3 m
Now, we calculate the distance covered during decelerated motion:
2as₂ = Vf² - Vi²
where,
a = deceleration = -4.5 m/s²
s₂ = distance covered during decelerated motion = ?
Vf = Final Velocity = 0 m/s
Vi = Initial Velocity = 11 m/s
Therefore,
2(-4.5 m/s²)s₂ = (0 m/s)² - (11 m/s)²
s₂ = (-121 m²/s²)/(-9 m/s²)
s₂ = 13.4 m
the total distance will be:
s = s₁ + s₂
s = 25.3 m + 13.4 m
<u>s = 38.7 m</u>
