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Allisa [31]
3 years ago
14

Can a fire have a shadow?

Physics
2 answers:
Anton [14]3 years ago
7 0

Answer:

can a fire have a shadow?

Yes it can actually.

edit:Fires can have shadows because they contain hot air and soot, and not because they contain light.

EleoNora [17]3 years ago
3 0

Answer:

No.

Explanation:

A shadow is basically the absence of light. Fire doesn't have a shadow cause fire is itself a source of light, so the wall or obstacle you'd be expecting it's shadow to fall on, would instead be covered by the light from the fire. Hence, fire has no shadow.

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A 1210-kg vehicle is moving along a horizontal surface with a speed of 28.3 m/s. What work (in J) must be done by the brakes to
ArbitrLikvidat [17]

Answer:

4.85*10^5 Joules

Explanation:

The work done in bringing the car to rest would be equivalent to the kinetic energy of the vehicle while it is in motion.

The kinetic energy of the vehicle is 1/2mv^2; where m is the mass and v is the velocity.

Work done=1/2*1210*28.3^2

Another approach would be to calculate the force applied and the braking distance of the vehicle and then applying the formula of work done. However, it would've been an unnecessary hassle.

6 0
3 years ago
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Bond [772]

Answer:

ok i searched it up in google and it showed links XDDDD

Explanation:

4 0
3 years ago
Student in ms sawyers class built balloon cars the balloon car works this way as the gas in the balloon is released the car move
RUDIKE [14]

Answer:

Third Law of Motion

Explanation:

7 0
3 years ago
The acceleration of a moving vehicles is 10 metre per second square what does it means ​
pochemuha

Answer:

Acceleration is the rate of change of velocity. What is commonly said as ‘ten meter per second squared’ can bee broken down into ‘ten meter per second per second.’ This gives us the true meaning of the term acceleration.

Just like ‘ten meter per second’ means increasing the displacement by ten meters every second, ‘ten meter per second per second’ means increasing the velocity by ten meters per second every second.

So, basically if you consider the case of a free fall motion, where ‘t’ stands for time and ‘v’ stand for velocity at that instant:

At,

t=0, v=0 m/s

t=1, v=0+10 m/s;

t=2, v=0+10+10 m/s;

t=3, v=0+10+10+10 m/s;

This can also be thought as a Arithmetic Progression where common difference ‘D’ is the acceleration(a), since it adds a 10 m/s to velocity every second and the first term ‘A’ stands for the initial velocity (u). Using this approach we can derive to the first equation of motion:

v = u + at

Hope this Answer Helps!!

Explanation:

plz mark me as a brainlest and thank my answer

3 0
3 years ago
Read 2 more answers
A 5.0-kg box is pulled by a horizontal force F applied to the top of the box. When the box meets a low doorstep, it begins to ro
NARA [144]

Answer:

the required minimum magnitude of the force F is 21 N

Explanation:

Given the data in the question,

m = 5 kg

width  = 60 cm

height = 80 cm

Let force is F represent in the image below,

so when the block about to rotate normal shifted to edge of cube

mg(w/2) = Fh

F = mg(w/2) / h

we know that g = 9.8 m/s²

we substitute

F = (5 × 9.8 ( 60/2)) / 70

F = (5 × 9.8 × 30 ) / 70

F = 1470 / 70

F = 21 N

Therefore, the required minimum magnitude of the force F is 21 N

5 0
3 years ago
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