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Nina [5.8K]
2 years ago
8

What variable does each of the symbols in the equation represent?

Physics
1 answer:
taurus [48]2 years ago
4 0

Answer:

Pls give the equation and for what is that equation for?

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What do you call a group of sea turtles?
Valentin [98]

Answer:

a bale

Explanation:

a bale is a group of turtles

8 0
3 years ago
Read 2 more answers
A 15-kilogram cart is at rest on a horizontal
Sergio [31]
The most likely answer to this problem would be (1) more mass and more inertia.

A 15-kilogram cart at rest and a 5-kilogram box would make up a 20-kilogram cart and box that is at rest on a horizontal surface. The mass changed into something more, of course, as a result of combining the two object into one and by combining the two objects' mass, the inertia that it previously possessed as a cart by itself was increased when the inertia of the box was also combined to the cart.
6 0
3 years ago
PART ONE
Helga [31]

Answer:

1.129×10⁻⁵ N

1.295 m

Explanation:

Take right to be positive.  Sum of forces on the 31.8 kg mass:

∑F = GM₁m / r₁² − GM₂m / r₂²

∑F = G (M₁ − M₂) m / r²

∑F = (6.672×10⁻¹¹ N kg²/m²) (516 kg − 207 kg) (31.8 kg) / (0.482 m / 2)²

∑F = 1.129×10⁻⁵ N

Repeating the same steps, but this time ∑F = 0 and we're solving for r.

∑F = GM₁m / r₁² − GM₂m / r₂²

0 = GM₁m / r₁² − GM₂m / r₂²

GM₁m / r₁² = GM₂m / r₂²

M₁ / r₁² = M₂ / r₂²

516 / r² = 207 / (0.482 − r)²

516 (0.482 − r)² = 207 r²

516 (0.232 − 0.964 r + r²) = 207 r²

119.9 − 497.4 r + 516 r² = 207 r²

119.9 − 497.4 r + 309 r² = 0

r = 0.295 or 1.315

r can't be greater than 0.482, so r = 0.295 m.

5 0
3 years ago
Answer the question below. Use the rubric in the materials for help if needed. Use details to support your response.
butalik [34]

Answer:

umm soo no wait what

Explanation:

5 0
3 years ago
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per
Brilliant_brown [7]

Answer:

a_{cp}=7.77m/s^2

Explanation:

The equation for centripetal acceleration is a_{cp}=\frac{v^2}{r}.

We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.

Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference C=2\pi r and the period T, then we have:

v=\frac{C}{T}=2\pi r f

Putting all together:

a_{cp}=\frac{(2\pi r f)^2}{r}=4 \pi^2f^2r=4 \pi^2(0.75Hz)^2(0.35m)=7.77m/s^2

4 0
3 years ago
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