wavelength =wavevelocity
--——————
Frequency
Frequency = 1/T => 1 / 6.73 = 0.1486
Wave velocity = L/T => 3.75 / 6.73 = 0.5572
Therefore, wave length = 0.5572/0.1486 = 3.75m
second question: How many seconds after the first snowball
should you throw the second so that they
arrive on target at the same time?
Answer in units of s.
Answer:
Part 1: 28°
Part 2: 1.367
Explanation:
Part 1:
Given: 62°
Simple
θ = 90°- 62°
<u>θ = 28°</u>
Part 2:
Y-direction
Δy
![t_{1} =\frac{2[16.2sin(62)]}{9.8}](https://tex.z-dn.net/?f=t_%7B1%7D%20%3D%5Cfrac%7B2%5B16.2sin%2862%29%5D%7D%7B9.8%7D)

![0=[16.2sin(28)]t_{2}+1/2(-9.8)t_{2}^{2}](https://tex.z-dn.net/?f=0%3D%5B16.2sin%2828%29%5Dt_%7B2%7D%2B1%2F2%28-9.8%29t_%7B2%7D%5E%7B2%7D)
![t_{2} =\frac{2[16.2sin(28)]}{9.8}](https://tex.z-dn.net/?f=t_%7B2%7D%20%3D%5Cfrac%7B2%5B16.2sin%2828%29%5D%7D%7B9.8%7D)

Δt
Δt
<u>Δt= 1.367s</u>
Hope it helps :)
Answer:
Explanation:
The formula S=(at^2)/2 will be used during the entire explanation.
1. 4 = (2t^2)/2
t = 2 s.
V = at = 2 * 2 = 4 m/s
2. 8 = (2t^2)/2
t = 2.8 s
iii. 2s
iv. 2.8 - 2 = 0.8s
Hope you understand)
Answer:
= 19 Ω, I = 0.105 A, V1 = 1.05 V and V2 = 0.95 V
Explanation:
The correct way to solve this type of problem is to find the current or voltage values for the equivalent resistance and from here find the other values.
For a series circuit the equivalent resistance is the sum of the resistance
= R1 + R2
= 10 +9
= 19 Ω
Let's use the equation for the voltage
V = I
I = V / 
I = 2/19
I = 0.105 A
In a series circuit the current is constant, so let's use the voltage equation for each resistor
V1 = I R1
V1 = 0.105 10
V1 = 1.05 V
V2 = 0.105 9
V2 = 0.95 V
Note that the sum of this voltage is the total voltage applied.
Answer:
0.541 nm
Explanation:
The condition for maxima is,

Here, m=0,1,2,.....
And d is the slit separation, m is the order of maxima,
is the wavelength.
Given that, the 17.3 eV electron posses a wavelength of

And the order of maxima is
.
And the angle at which first order maxima occur is,
.
Put these values in maxima condition while solving for d.

Therefore, the slit separation is 0.541 nm.