An ac generator provides emf to a resistive load in a remote factory over a two-cable transmission line. At the factory a step-
1 answer:
Answer:
a) 1.875 volts
b) 5.86 W
Explanation:
Given data:
transmission line resistance = 0.30/cable
power of the generator = 250 kW
if Vt = 80 kV
<u>a) Determine the decrease V along the transmission line </u>
Rms current in cable = P / Vt = 250 / 80 = 3.125 amps
hence the rms voltage drop ( Δrmsvoltage )
Δrmsvoltage = Irms* R = 3.125 * 2 * 0.30 =<em> 1.875 volts </em>
<u>b) Determine the rate Pd at which energy is dissipated in line as thermal energy </u>
Pd =
= 3.125^2 * 2* 0.30 = <em>5.86 W</em>
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The induced emf in the loop is -1500 μ V or - 0.0015 V .
According to the question
A conducting loop in the form of a circle is placed perpendicular to a magnetic field of 0. 50 t.
i.e
Magnetic field (B) = 0. 50 T
Area of circle or loop =
Now,
The area of the loop decreases at a rate of 3. 0 × 10⁻³ m/s
i.e
dA = 3. 0 × 10⁻³ meter²
dt = 1 sec
As per the formula of Induced e.m.f in the loop
emf is dependent on number of turns of coil, shape of the coil, strength of magnet and speed with which magnet is moved. Emf is independent of resistivity of wire of the coil.
where A is the area of the loop.
Now ,
Substituting the values in the formula
e = - 0.0015 V
OR
e = -1500 * 10⁻⁶ V
e = -1500 μ V
Negative just signifies emf will such be induced that current induced will oppose change in magnetic field though it
To know more about induced emf here:
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