An ac generator provides emf to a resistive load in a remote factory over a two-cable transmission line. At the factory a step-
1 answer:
Answer:
a) 1.875 volts
b) 5.86 W
Explanation:
Given data:
transmission line resistance = 0.30/cable
power of the generator = 250 kW
if Vt = 80 kV
<u>a) Determine the decrease V along the transmission line </u>
Rms current in cable = P / Vt = 250 / 80 = 3.125 amps
hence the rms voltage drop ( Δrmsvoltage )
Δrmsvoltage = Irms* R = 3.125 * 2 * 0.30 =<em> 1.875 volts </em>
<u>b) Determine the rate Pd at which energy is dissipated in line as thermal energy </u>
Pd =
= 3.125^2 * 2* 0.30 = <em>5.86 W</em>
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Answer:
The girl has greater tangential acceleration
Explanation:
The angular acceleration () of the merry go round is equal to the rate of the change of the angular velocity,
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Since all the points of the merry go round complete 1 circle in the same time, the angular velocity of each point of the merry go round is the same, and so all the points also have the same angular acceleration.
The tangential acceleration instead is given by
where
is the angular acceleration
r is the distance from the centre of the merry go round
Since the girl is near the outer edge and the boy is closer to the centre, the value of r for the girl is larger than for the boy, so the girl has greater tangential acceleration.