An ac generator provides emf to a resistive load in a remote factory over a two-cable transmission line. At the factory a step-
1 answer:
Answer:
a) 1.875 volts
b) 5.86 W
Explanation:
Given data:
transmission line resistance = 0.30/cable
power of the generator = 250 kW
if Vt = 80 kV
<u>a) Determine the decrease V along the transmission line </u>
Rms current in cable = P / Vt = 250 / 80 = 3.125 amps
hence the rms voltage drop ( Δrmsvoltage )
Δrmsvoltage = Irms* R = 3.125 * 2 * 0.30 =<em> 1.875 volts </em>
<u>b) Determine the rate Pd at which energy is dissipated in line as thermal energy </u>
Pd =
= 3.125^2 * 2* 0.30 = <em>5.86 W</em>
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Answer:
minimum stopping distance will be d = 75 m
Explanation:
Maximum force exerted by the bracket is given as
F = 9000 N
now we know that mass of the object is
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Complete Question
The weights of soy patties sold by a diner are normally distributed. A random sample of 15 patties yields a mean weight of 3.8 ounces with a sample standard deviation of 0.5 ounces. At the 0.05 level of significance,perform a hypothesis test to see if the true mean weight is less than 4 ounce.
Answer:
Yes the true mean weight is less than 4 ounce
Explanation:
From the question we are told that
The random sample is
The mean weight is
The standard deviation is
The level of significance is
So
The null hypothesis is
The alternative hypothesis is
Generally the critical value which a bench mark to ascertain whether the null hypothesis is true or false is mathematically represented as
This value is obtained from the critical value table
Generally the test statistics is mathematically represented as
=>
So since ST is less than then the null hypothesis would be rejected and the alternative hypothesis would be accepted so
Thus the true mean weight is less than 4
Answer:
L=0.654 m
Explanation:
<u>Concepts and Principles </u>
1- The speed of sound in air is expressed as a function of the temperature of air as follows:
v=(331 m/s)√(1+T_C/273°C) (1)
where 331 m/s is the speed of sound in air at temperature 0°C and Tc is the temperature of air in Celsius.
<u>Standing Wave Patterns in Pipes: </u>
A pipe open at both ends can have standing wave patterns with resonant frequencies:
f=v/λ=nv/2L n=1,2,3.........
where v is the speed of sound in air.
<u>Given Data </u>
f_1 (fundamental frequency of the flute) = 262 Hz
T (temperature of the air) = 20°C
The flute is open at both ends.
<u>Required Data </u>
We are asked to determine the length of the tube.
<u>Solution</u><u> </u>
The speed of sound in air at temperature T = 20°C is found from Equation (1):
v=(331 m/s)√(1+T_C/273°C)
=342.91 m/s
The fundamental frequency of the flute is found by substituting n = 1 into Equation (2):
f=v/2L
Solve for L:
L=v/2f_1
L=0.654 m
