Answer: see below
<u>Step-by-step explanation:</u>
1) 10, 2, 1.2, 1.12, 1.112, 1.1112
t₁ = 10
t₂ = 10/10 + 1 = 2
t₃ = 2/10 + 1 = 1.2
t₄ = 1.2/10 + 1 = 1.12
t₅ = 1.12/10 + 1 = 1.112
t₆ = 1.112/10 + 1 = 1.1112
2) 10, 2, -2, -4, -5, -5.5, ...
t₁ = 10
t₂ = 10/2 - 3 = 2
t₃ = 2/2 - 3 = -2
t₄ = -2/2 - 3 = -4
t₅ = -4/2 - 3 = -5
t₆ = -5/2 - 3 = -5.5
Answer:
(x - 3)(x + 1)(x + 5)
Step-by-step explanation:
I'd use synthetic division instead. If we were to find the roots of the given polynomial, we could from them write the factors as well.
The divisor x + 5 corresponds to root x = -5. Setting up synthetic div.,
-5 ) 1 3 -13 -15
-5 10 +15
-----------------------------
1 -2 -3 0
Since the remainder is 0, we know that -5 is a root and (x + 5) is a factor. Moreover, we know that the coefficients of the quotient are 1, -2 and -3.
1x² - 2x - 3 can be factored: the factors are (x - 3) and (x + 1).
So the end result for this problem is (x - 3)(x + 1)(x + 5).
25.) D
26.) C
27.) B
I hope this helps love! :)
