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Dimas [21]
3 years ago
9

Does anyone know the answer?

Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Answer: 11/18

Step-by-step explanation: I've attached the explanation

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Suppose the band sells erasers for $2 per package and pencils for $5 per package. The band sells 220 packages in all and earns a
garik1379 [7]
Let e=erasers and p=pencils. So we know the total amount of erasers plus pencils sold is equal to 220. Therefore,

e + p = 220
We also know the cost of erasers and pencils totaled to $695 in earnings and so:

2e + 5p = 695
and so those are your two equations.

5 0
3 years ago
Solve the system by substitution.
Iteru [2.4K]

Answer:

I gave you most of the answer. I'll let you check my work and find the point using the solution.

Step-by-step explanation:

The first thing we do is we divide by negative one in the first equation to get

y = -x.

-3x + 3y = -36

Plug in y = -x and get

-3x + 3(-x) = -36

= -3x - 3x = -36

This equals -6x = -36

divide both sides by -6 and you get 6. 6 is your x value

Plug 6 back in to the second equation.

-3x + 3y = -36

-3(6) + 3y = -36

-18 + 3y = -36

3y = -18

y = -6

3 0
2 years ago
If a bicyclist travels 3 miles in 15 minutes, how far will he travel in 25 minutes maintaining a constant speed? (includes units
Irina-Kira [14]

<u>Answer:</u>

5 miles

<u>Step-by-step explanation:</u>

15 × ? = 25

3 × ? = ?

15 × 1 and 2/3 = 25

3 × 1 and 2/3 = ?

3 × 1 and 2/3 = 5

Your welcome and Rate as Brainliest

3 0
3 years ago
Read 2 more answers
To transmit information on the internet, large files are broken into packets of smaller sizes. Each packet has 1,500 bytes of in
Alexeev081 [22]

Answer:

Step-by-step explanation:

Jjhu

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3 years ago
Explain how you can find any power of 1
My name is Ann [436]

\bf \begin{array}{llll}&#10;1^2\implies 1\cdot 1\implies &1\\\\&#10;1^3\implies 1\cdot 1\cdot 1\implies &1\\\\&#10;1^{100}\implies \stackrel{\textit{100 times}}{1\cdot 1...}\implies &1\\\\&#10;1^{1000000}\implies \stackrel{\textit{a million times}}{1\cdot 1....}\implies &1\\\\&#10;1^{x}\qquad \{x|~~x\in \mathbb{Z}\}\implies &1&#10;\end{array}

6 0
3 years ago
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