As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.
Then friction force = 80 Newtons but in the opposite direction.
Friction force = Mu * Normal force exerted by ground = Mu * weight of box
So we find Mu.
Mu = coefficient of friction between box and horizontal surface
= Force of friction / weight = 80 / 50 * 9.81 = 0.163
When an identical box is placed on top, the force of friction is
= Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons
Answer:
D. 20.4m
Explanation:
assuming there is no initial velocity, where v=final velocity, g=acceleration due to gravity, and t=time
v = g*t
20 = 9.8*t
t =2.03 s
y = (1/2) g t^2 where y=vertical distance, g=acceleration due to gravity, and t=time
y = 4.9 (2.03)^2
y = 20.4 meters
Answer:
850N
Explanation:
The step by step is in the attachment.
Answer: is C
Expiation: you can find the answer on quizlet and it’s diverging mirror so the answer is C