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Sedbober [7]
3 years ago
10

-List ten different waves that you encounter in everyday life. Be specific, don't just say "sound

Physics
1 answer:
Nady [450]3 years ago
6 0

Answer:

1.Radio waves from using your TV.

2. microwaves you are in satellites.

3.UV light waves come from sunlight

4.x ray waves used at the doctors office

5. infrared waves are in remote controls when sending signals.

I don't know if I can think of another 5 right now. but I hope this helps.

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A 9kg bowling ball rolls of a table and strikes the ground. If the ball is in the air for 0.5 sec, how fast is the ball moving w
stepladder [879]
Falling for 1 second it would have accelerated to 9.8 metres per second 

so the answer is 9.8*0.05=0.49m/sec 

that is your answer
4 0
3 years ago
The vernal equinox marks the first day of spring. What happens on this day? The north pole is tilted toward the sun. Day and nig
Drupady [299]

Answer:

Day and night on Earth are equal.

Explanation:

Vernal means fresh or new like the spring. The vernal equinox, because it signals the beginning of spring. On this day, the Sun is exactly above the Equator and day and night are of equal length. In the northern hemisphere, the vernal equinox is around March 20 or 21 when the Sun crosses the celestial equator going north while in the southern hemisphere, the vernal equinox is around September 22 or 23 when the Sun moves south across the celestial equator.

5 0
3 years ago
Which formulas might be used to find the velocity based on a position-time graph?
Alex787 [66]
The formula to get the velocity is V=D/T. First you need to determine the distance and time at a certain point and plug it into the equation and that will be your velocity at that point. To get it between two points you complete the directions two times and find the average or use the slope formula, slope = rise/run; slope = (y2 - y1) / (x2 - x1). 
6 0
4 years ago
Work done per unit time :- a. force b. power c. energy d. momentum​
iragen [17]
The Answer: B. Power
7 0
3 years ago
The speed of an arrow fired from a compound
san4es73 [151]

Answer:

A.) The arrow`s range is 624,996 m

B.) The arrow`s range is 846.887 m, when the horse is galloping

Explanation:

We have a case of oblique movement. In these cases the movement in the X axis is a Uniform Rectelinear Movement (URM), and a Uniform Accelerated Movement (UAM) in the Y axis.

By the way, the equations that we use for the X axis will be from URM, and those for the Y axis wiil be from UAM.

<u>Equations</u>

X axis:

X=v_{ox}*t

v_{0x} =v_0cos(\alpha)

Y axis:

Y= Y_0 +v_{y0} t - \frac{g}{2} t^2

A.) First, it is necessary to know t, total time.

To figure out t value, we use UAM, since time is determined by this movement.

Now, at the end of the movement, Y=0, then

0= Y_0 +v_{y0} t - \frac{g}{2} t^2

0=2.4m+79m/s*sin(39)t-(1/2*9.81m/s^2)t^2

Caculate the segcond degree equation to obtain the two possible values for t:

t_1= 10.18 \\t_2= -0.04046

But, in physics, time it could not be negative, so we take t_1= 10.18

Caculate now:

X=79m/s*cos(\39)*10.18s= 624.996 m

B.) Now, the narrow has an additional speed, that could be sum to the speed due to the bow.

v_0= 79m/s+13m/s= 92m/s

Using the same procedure that item A, caculate X

First, we need to know the new time

0=2.4m+92m/s*sin(39)t-(1/2*9.81m/s^2)t^2

And we obtain:

t_1=11.845s\\t_2=-0.041s

One more time, we take the positive time: t_1=11.845s

Finally:

X=92m/s *cos(39)*11.845s=846.887 m

6 0
3 years ago
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