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daser333 [38]
3 years ago
10

Ton is used for measure very big masses.right or wrongscience ​

Physics
2 answers:
nlexa [21]3 years ago
4 0

Answer:

Explanation:

The correct answer is right

adoni [48]3 years ago
3 0

Answer:

True

Explanation:

Ton is a unit that is used to measure huge masses like cars, trucks and huge boxes

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A person with a remote mountain cabin plans to install her own hydroelectric plant. A nearby stream is 3.00 m wide and 0.500 m d
Lubov Fominskaja [6]

Answer:

The power she can generate is 185.22 KW.

Explanation:

<h3><u>DATA</u></h3>

3.00m wide and 0.500m deep.

Cross sectional area = 1.500m^2

Velocity = 1.35m/s

Volumetric flow rate = Av = 18.00m^3/s

Mass flow rate = 18,000kg/s

Height = 4.20m

25.0% efficiency

<h3><u> FORMULA:</u></h3>

P = dE / dt * eff

<h3><u>SOLUTION:</u></h3>

18,000kg/s (9.8m/s^2) (4.20m) (25%) = 185,220 watts

= 185 kw

6 0
3 years ago
PLS ANSWER FAST WILL GIVE BRAINLEST!!!!
amid [387]

Answer:

F = 500 N

Explanation:

F = m × a

F = 1,000 × 0.5

F = 500 kg m/s²

F = 500 N

7 0
3 years ago
When light passes through an object unchanged, scientists call that process _____.
Nataly [62]

<u>Answer</u>:

When light passes through an object unchanged, scientists call that process Transmission.

<u>Explanation</u>:

Transmission is the process where all the light that is passed through the material moves via the material without being absorbed. The Transmission depends on the affected radiation.The Transmittance of the medium is defined as the ratio between transmitted radiant power and incident radiant power. The light that is passed through the medium and not reflected will be either scattered or reflected. The light can be transmitted only through transparent or translucent material. Opaque object does not allows transmission of light.

5 0
3 years ago
Objects in free fall are weightless. true or false???
frez [133]

The answer is false

7 0
3 years ago
A laser of wavelength 720 nm illuminates a double slit where the separation between the slits is 0.22 mm. Fringes are seen on a
kumpel [21]

Answer:

The appropriate solution is "2.78 mm".

Explanation:

Given:

\lambda = 720 \ nm

or,

  = 720\times 10^{-9} \ m

D=0.85 \ m

d = 0.22 \ mm

or,

  =0.22 \times 10^{-3} \ m

As we know,

Fringe width is:

⇒ \beta=\frac{\lambda D}{d}

hence,

Separation between second and third bright fringes will be:

⇒ \theta=\beta=\frac{\lambda D}{d}

       =\frac{720\times 10^{-9}\times 0.85}{0.22\times 10^{-3}}

       =2.78\times 10^{-3} \ m

or,

       =2.78 \ mm

8 0
2 years ago
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