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3 years ago

How is subtracting integers related to adding integers

Mathematics

2 answers:

Sedbober [7]3 years ago

5 0

answer: well i thing subtracting and adding integers are related because they both can be solved using an number line

Sloan [31]3 years ago

4 0

We can use the number line as a model to help us visualize adding and subtracting of signed integers. Just think of addition and subtraction as directions on the number line. There are also several rules and properties that define how to perform these basic operations.

To add integers having the same sign, keep the same sign and add the absolute value of each number.

To add integers with different signs, keep the sign of the number with the largest absolute value and subtract the smallest absolute value from the largest.

Subtract an integer by adding its opposite.

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3 years ago

What is the volume of a rectangular prism with a length

lana [24]

The volume of the rectangular prism is 1 $inch^{3}$ , If the rectangular prism have a length of 2 inches, a width of 1 inch, and a height of 1/2 inch.

Step-by-step explanation:

The given is,

Let, l - Length of the rectangular prism

w - Width of the rectangular prism

h - Height of the rectangular prism

Step:1

From the given,

l - 2 inches

w - 1 inch

h - $\frac{1}{2}$ inch

Step:2

Formula for the volume of a rectangular prism is,

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Result:

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7 0

4 years ago

Read 2 more answers

Determine the values of the unlabeled parts of the triangle.

____ [38]

Answer:

∠Q = 63.4º, PQ = 2, QO = 4.47

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.

Triangle POQ is a right angled triangle because ∠P = 90°. Also, ∠O = 26.6°.

Therefore in ΔPOQ: ∠P + ∠O + ∠Q = 180° (sum of angles in a triangle).

90 + 26.6 + ∠Q = 180

∠Q + 116.6 = 180

∠Q = 180 - 116

∠Q = 63.4°

We can find PQ and QO using sine rule. Sine rule for ΔPOQ is given as:

$\frac{PO}{sin Q}= \frac{PQ}{sinO}= \frac{QO}{sin P}\\\\Finding\ PQ :\\\\\frac{PO}{sin Q}= \frac{PQ}{sinO}\\\\\frac{4}{sin(63.4)} =\frac{PQ}{sin(26.6)}\\\\PQ= \frac{4}{sin(63.4)} *sin(26.6)\\\\PQ = 2\\\\Also\ finding\ QO:\\\\\frac{PO}{sin Q}= \frac{QO}{sinP}\\\\\frac{4}{sin(63.4)} =\frac{QO}{sin(90)}\\\\QO=\frac{4}{sin(63.4)} *sin(90)\\\\QO = 4.47$

4 0

3 years ago