The ticket price that would maximize the total revenue would be $ 23.
Given that a football team charges $ 30 per ticket and averages 20,000 people per game, and each person spend an average of $ 8 on concessions, and for every drop of $ 1 in price, the attendance rises by 800 people, to determine what ticket price should the team charge to maximize total revenue, the following calculation must be performed:
- 20,000 x 30 + 20,000 x 8 = 760,000
- 24,000 x 25 + 24,000 x 8 = 792,000
- 28,000 x 20 + 28,000 x 8 = 784,000
- 26,000 x 22.5 + 26,000 x 8 = 793,000
- 27,200 x 21 + 27,200 x 8 = 788,000
- 26,400 x 22 + 26,400 x 8 = 792,000
- 25,600 x 23 + 25,600 x 8 = 793,600
- 24,800 x 24 + 24,600 x 8 = 792,000
Therefore, the ticket price that would maximize the total revenue would be $ 23.
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The answer is:
-2m²+4n²-mn-2m+5n
aka letter c in algebra nation
Answer:84
Step-by-step explanation:because 7x12=84
Answer: Horizontal Asymptote: y = 7
Y = 3^x + 7
Step-by-step explanation:
Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 7
firstly, I'd like to point out the graph is misleading, if AC is 10 it should be the shorter sides, but it shows as the longer side there.
let's bear in mind that in a rhombus, all sides are equal, even though they may be slanted, the diagonals meet at right-angles always, so the center is simply four 90° angles, and the diagonals bisect each other, namely they cut each other in equal halves.
check the picture below.
