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SIZIF [17.4K]
4 years ago
5

How to solve 29+d=54;24,25,26

Mathematics
1 answer:
oee [108]4 years ago
3 0
29 + d = 54
subtract 29 from both sides
d= 54-29
d=25
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zheka24 [161]

The magnitude of WX is  \sqrt{29}  ⇒ c

Step-by-step explanation:

The magnitude of XY (its length) where,

  • X=(x_{1},y_{1},z_{1})
  • Y=(x_{2},y_{2},z_{2})

is IXYI = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}+(z_{2}-z_{1})^{2}}

∵ W = (-2 , 8 , -3)

∵ X = (1 , 4 , -1)

- To find the magnitude of WX use the formula above

∴ x_{1} = -2 and x_{2} = 1

∴ y_{1} = 8 and y_{2} = 4

∴ z_{1} = -3 and z_{2] = -1

- Substitute these values in the rule above

∵ IWXI = \sqrt{(1--2)^{2}+(4-8)^{2}+(-1--3)^{2}}=\sqrt{9+16+4}

∴ IWXI = \sqrt{29}

The magnitude of WX is  \sqrt{29}

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If s(x) = x-7 and f(x) = 4x? – X+3, which expression is equivalent to (tos)(x)?
lesya692 [45]

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Step-by-step explanation:

Let s(x)=x-7 and t(x)=4x^2-x+3 .

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Before I continue this means replace the orginal x in t with x-7.

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4(x-7)^2-(x-7)+3

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Factors of denominator will be,

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