3648Common Factors:GCF:What is it?

Mathematics

1 answer:

Lady_Fox [76]3 years ago

4 0

Answer: 6

Step-by-step explanation: 36 divided by 6 equals 6

48 divided by8 is 6

common factor is 6

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Should any factors be accounted for when explaining how to solve an equation?

Veronika [31]

Yes, it should be taken into account

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3 years ago

Show that the transformation T defined by T(x1, x2) = (2x1 - 3x2, X1+4, 5x2) is not linear.

erastovalidia [21]

Let u = (1, 0) and v = (0, 1). Then

T (u) = (2*1 - 3*0, 1 + 4, 5*0) = (2, 5, 0)

T (v) = (2*0 - 3*1, 0 + 4, 5*1) = (-3, 4, 5)

=> T (u) + T (v) = (-1, 9, 5)

but

T (u + v) = T (1, 1) = (2*1 - 3*1, 1 + 4, 5*1) = (-1, 5, 5)

=> T (u + v) ≠ T (u) + T (v)

which means T does not preserve addition, so it is not linear.

4 0

3 years ago

The Parry Glitter Company recently loaned $300,000 to FIX 92, a local radio station. The radio station signed a noninterest-bear

melomori [17]

Answer:

The Parry Glitter Company

The Parry Glitter Company should record the Notes Receivable as $300,000.

It should also record the interest receivable per year as $24,000 and the advertising cost as $24,000 per year. These bring into the accounting records the interest revenue and also the advertising expense, which eventually cancel each other.

Step-by-step explanation:

a) Data and Calculations:

Notes Receivable = $300,000

If the notes receivable are repaid at the end of 3 years and it is assumed that the interest on the notes receivable = 8%

Therefore, the cost of the free advertising will be equal to $24,000 ($300,000 * 8%), which is the cost of the interest to the radio station.

8 0

3 years ago

24-5 2 plssssss help

Burka [1]

Answer:

19 or -28

Step-by-step explanation:

is it 24 - 5 or 24 - 52?

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3 years ago

Read 2 more answers

The graph above is a transformation of the function x2 Write an equation for the function graphed above

lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

$(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2) \ \ \ \ y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \ \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right \\$