Answer:
formula: y-y1 = m(x-x1)
Step-by-step explanation:
General:
1. find 2 points directly on the line and apply the formula y2-y1 over x2-x1 this answer equals m
2. then add it into the formula y-y1 = m(x-x1) remember x and y are variables so only put numbers in y1 and x1
3. solve the problem
Example:
line 1:
1. y2-y1 over x2-x1 is 4-6 over 6-4 = -1
2. y-6 = -1(x-(-4) or y-6 = -1(x+4)
3. y-6 = -1x-4
4. y = -1x-2
3. the gradient equals: y = -1x-2
Hope this helps :) Let me know if you need a better example
The resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
According to the given question.
We have an equation

So, to find the resulting equation of the above equation we need to simplify.
First we will take LCD



Multiply both the sides by x.

Again multiply both the sides by x



Factorize the above equation
⇒3x(x+6)+2(x+6) = 0
⇒(3x + 2)(x+6) = 0
⇒ x = -2/3 or x = -6
Hence, the resulting equation after simplyfing the given equation is 3x^2 + 20x + 12 = 0 and whoose solutions are x = -2/3 or x = -6.
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Answer:
Step-by-step explanation:
Subtract 7y7y from both sides.
-4x=18-7y−4x=18−7y
2 Divide both sides by -4−4.
x=-\frac{18-7y}{4}x=−
4
18−7y
Answer:
16
Step-by-step explanation:
-21x+121
x=5
substitute x
-21(5)+121=-105+121=16
A linear equation is an equation between two variables that gives a straight line when plotted on a graph.