The element is most likely PHOSPHORUS.
Phosphorus is an element with an atomic number of 15. The electronic configuration of the element is 2,8,5. This configuration implies that, each atom of phosphorus has three sub shell, the first sub shell has 2 electrons, the second has 8 electrons while the outermost sub shell has 5 electrons. The electrons in the outermost shell are also called the valence shell. Thus, phosphorus has 5 electrons in its valence shell.
From the above statement, John can infer that the rock underwent metamorphism and also is not altered by heat or pressure.
<u>Explanation</u>:
- Metamorphic rock is an igneous sedimentary rock and although when put through heat the rock becomes hot but does not alter its shape or melt. If the rock melts then it is only an igneous rock and not a sedimentary one.
- During metamorphism, the chemical and the mineral content of prolith are changed due to changes in the environment based on physical and chemical conditions.
- Even though the rocks remain solid, fluid is present between the macroscopic spaces.
- This gives "The Geologist" accurate information of what happens beneath the earth during the formation of mountains.
- Metamorphic rocks are like probes that go down the earth and comes back giving information of what happens underneath the surface.
The equilibrium expression shows the ratio
between products and reactants. This expression is equal to the concentration
of the products raised to its coefficient divided by the concentration of the
reactants raised to its coefficient. The correct equilibrium expression for the
given reaction is:<span>
<span>H2CO3(aq) + H2O(l)
= H3O+(aq) + HCO3-1(aq)
Kc = [HCO3-1] [H3O+] / [H2O] [H2CO3]</span></span>
U^235Number of protons = 92 pNumber of electrons = 92 eNumber of neutrons = 235 – 92 = 143n
U^238Number of protons = 92pNumber of electrons = 92eNumber of neutrons = 238 – 92 = 146n
Electron configuration of U atom U = 92 U = [Rn] 5f^6 6d^0 7s^0 U = [Rn] 5f^36d^17s^2, 7s is completely filled and others are less than half filled.
(_92^238)U Decays to (_90^234)ThIt loses 2 protons, 2 electrons and loses 2 neutrons Th = [Rn] 6d^2 7s^2 There is no electron in 5f subshell and 6d contains 2e^-, 7s completely filled
